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larisa [96]
3 years ago
8

**URGENT** PLEASE HELP WILL GIVE BRAINLIEST

Mathematics
1 answer:
Gnoma [55]3 years ago
6 0

Answer:

they are both 0 since they would not appear on a graph

Step-by-step explanation:

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Solve: d |6n+7|=8 can you guys answer me plezzzzzzzz
likoan [24]

Answer: -5/2 or 1/6

Step-by-step explanation:

I6n + 7I = 8

Therefore (6n + 7) = 8 or -8 because modulus means we're only getting it's absolute value, (it's positive value) meaning it could equal 8 or -8 before it's modulus'ed.

Therefore 6n + 7 = 8

or 6n + 7 = -8

Leaving us with:

6n = 1

6n = -15

So n = 1/6

or n = -5/2 (-2.5)

7 0
3 years ago
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What is the domain for y=2x
Snowcat [4.5K]

Answer:

y ...................

7 0
4 years ago
Drag the tiles to the boxes to form correct pairs
Brums [2.3K]

Answer:

1) sin^{-1}(\frac{1}{\sqrt{2} })=45

2) cos^{-1}(\frac{\sqrt{3} }{2})=30

3) tan^{-1}(\sqrt{3})=60

4) sin^{-1}(1)=90

Step-by-step explanation:

1) Value of sin^{-1}(\frac{\sqrt{2} }{2}) =sin^{-1}(\frac{1}{\sqrt{2} })

since sin45° = 1/√2

Therefore sin^{-1}(\frac{1}{\sqrt{2} })=45

2).Value of cos^{-1}(\frac{\sqrt{3} }{2})

Since cos 30° = √3/2

Therefore cos^{-1}(\frac{\sqrt{3} }{2})=30

3). Value of tan^{-1}(\frac{3}{\sqrt{3} }) = tan^{-1}(\sqrt{3})=60

since tan 60° = √3

therefore tan^{-1}(\sqrt{3})=60

4). Value of sin^{-1}(1)

Since sin90°=1

Therefore sin^{-1}(1)=90

3 0
3 years ago
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Gold chains sell for $2.50 per inch. How much did ryan spend for an 18-inch gold chain?​
White raven [17]
The answer is 45 because 2.50 times 18=45
6 0
3 years ago
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Shelley is searching online for airline tickets. Two weeks​ ago, the cost to fly from Orlando to Boston was ​$210. Now the cost
Brums [2.3K]

Answer:

1) It would be about a 55% increase. 2) It would be about a 79% increase

Step-by-step explanation:

I used process of elimination to figure out how much of a percentage would be needed by just multiplying 210 by different percentages until I found the answer.

Sorry I don't have like a definite formula or anything for you to figure these questions out... I hope someone else answers with a more definite answer!

3 0
3 years ago
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