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3 years ago

15

There are 36 pencils in 6 packs. Igor wants to know how many pencils are in 1 pack. Elsa wants to know how many pencils are in 3

packs.

2 answers:

enyata [817]3 years ago

6 0

Igor: 6 pencils: 1 pack
Elsa: 18 pencils: 3 packs

Grace [21]3 years ago

4 0

There are 6 pencils in 1 pack. There are 18 pencils in 3 packs.

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Help thanks 7.04 love u guys

Ugo [173]

Answer:

D. $-\frac{3}{4}$

Step-by-step explanation:

The given equation is

$4y=8x-3$

When we divide through by 4 we get;

$y=2x-\frac{3}{4}$

Comparing to

y=mx+c,

The y-intercept is $-\frac{3}{4}$

The corrrect choice is D.

3 0

3 years ago

Read 2 more answers

if 3 half-gallon containers of ice cream on sale for $6.69,what is the price for 2 half-gallon containers?

kvv77 [185]

<h3>Answer: $4.46</h3>

===================================================

Work Shown:

3 containers = 6.69 dollars

3/3 containers = 6.69/3 dollars .... divide both sides by 3

1 container = 2.23 dollars

2*(1 container) = 2*(2.23 dollars) ... multiply both sides by 2

2 containers = 4.46 dollars

A shortcut is to start with "3 containers = 6.69 dollars" and multiply both sides by 2/3

Each mention of "container" refers to a half-gallon container.

6 0

3 years ago

Two particles travel along the space curves r1(t) = t, t2, t3 r2(t) = 1 + 2t, 1 + 6t, 1 + 14t . Find the points at which their p

GuDViN [60]

Answer:

A) points at which paths intersect : (1,1,1) ; (2,4,8)

B) DNE

Step-by-step explanation:

A) To find the points in which the particle paths intersect, it is necessary to find the values of t for which the three components of both vectors are equal:

$t_1=1+2t_2\\\\t_1^2=1+6t_2\\\\t_1^3=1+14t_2$

you replace t1 from the first equation in the second equation:

$(1+2t_2)^2=1+6t_2\\\\1+4t_2+4t_2^2=1+6t_2\\\\4t_2^2-2t_2=0\\\\t_2(2t_2-1)=0\\\\t_2=0\\\\t_2=\frac{1}{2}$

Then, for t2 = 0 and t2=1/2 you obtain for t1:

$t_1=1+2(0)=1\\\\t_1=1+2(\frac{1}{2})=2$

Hence, for t1=1 and t2=0 the paths intersect. Furthermore, for t1=2 and t2=1/2 the paths also intersect.

The points at which the paths intersect are:

$r_1(1)=(1,1,1)=r_2(0)=(1,1,1)\\\\r_1(2)=(2,4,8)=r_2(\frac{1}{2})=(2,4,8)$

B) You have the following two trajectories of two independent particles:

$r_1(t)=(t,t^2,t^3)\\\\r_2(t)=(1+2t,1+6t,1+14t)$

To find the time in which the particles collide, it is necessary that both particles are in the same position on the same time. That is, each component of the vectors must coincide:

$t=1+2t\\\\t^2=1+6t\\\\t^3=1+14t$

From the first equation you have:

$t=1+2t\\\\t=-1$

This values does not have a physical meaning, then, the particle do not collide

answer: DNE

5 0

3 years ago

What do you already know about linear relationships?

inna [77]

Answer:

A linear relationship (or linear association) is a statistical term used to describe a straight-line relationship between two variables. Linear relationships can be expressed either in a graphical format or as a mathematical equation of the form y = mx + b.

8 0

3 years ago

To convert 2/3 into an equivalent fraction with a denominator of 18, we could multiply only the denominator of 2/3 by.

Naya [18.7K]

Answer:

the answer is true

Step-by-step explanation:

3 0

3 years ago