At 0.01 significance level the hypothesis is rejected.
Null Hypothesis (H₀): The sample data occurs purely from chance.
Alternative Hypothesis (H₁): The sample data is influenced by some non-random cause.
If the p-value of the hypothesis test is less than some significance level (e.g. α = .01), then we can reject the null hypothesis and conclude that we have sufficient evidence to say that the alternative hypothesis is true.
Given that,
x = 28
s = 2.9
μ = 31
n = 8
α = 0.01
Then, the Null Hypothesis : H₀ = 31
The Alternate Hypothesis : H₁ < 31
The average number of cigeratte smoker per day is less than 31.
Test Statistics:
t = x -μ / s√n
= 28 - 31/ 2.9√8
= -3/ 8.41
= -0.356
Since the p-value of 0.0046 is less than the significance level of 0.01, the auditor rejects the null hypothesis.
Learn more about Null hypothesis:
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Let n = the unknown number
"Quotient of 82 and a number" translates to 82 / n
"decreased by 26 tells you you're subtracting 26.
82/n - 26 or
Answer: $33,400 ✌️
A liability is anything you owe or any debt you have to pay back.
Answer:
the largest divisor is less than the square root of that number
Step-by-step explanation:
Pick any number between 900 and 950 . For example I choose 937 . Now taking the square root of 937 would give 30.61
So divide 937 with all the primes less than 30.61
937/2, 937/3, 937/5,...................937/29
29 would be the largest divisor which is less than the square root of 937 .
29< 30.61
But if you check 937 does not divide wholly with any of the primes hence it is a prime number itself.
If any number such 925 is chosen and it gets divided wholly by another prime like 5
925 /5= 185 so it is not a prime number
Answer:
Jason has $58.20 and Jeff has $13.80.
Step-by-step explanation:
Let x represent the amount of money Jason has, and y represent the amount of money Jeff has.
We know that together they have $72. So, we can write the following equation:
We know that Jason has three <em>more</em> than four <em>times</em> the amount of money Jeff has. So:
This is a system of equations. We can solve it by using substitution. Let's substitute the second equation into the first. This yields:
Combine like terms:
Subtract 3 from both sides:
Divide both sides by 5:
So, Jeff has $13.80
We know that Jason has three more than four times the amount of money Jeff has.
Therefore, Jason has:
Multiply and add:
So, Jason has $58.20 and Jeff has $13.80.
And we're done!
