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3 years ago

15 POINTS!!! I just need to know if I do 1 4/9 - 1 8/11 or the other way around very simple!

Mathematics

2 answers:

Verdich [7]3 years ago

5 0

<h3>- - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - </h3>

➷ You need to do $1 \frac{8}{11} - 1\frac{4}{9}$

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ Hannah ♡

andriy [413]3 years ago

3 0

Wowwwwww I rlly don’t get this at alll

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What are my chances...

soldi70 [24.7K]

Answer:

Step-by-step explanation:

G = 1

Total = 10

1/10 = 0.1

4 0

2 years ago

Can you help me? i do not get it

Allushta [10]

Let's assume the question is to find the area of the shaded region.

7. We have to assume the bottom right angle is right as well.

Consider the white triangle at the bottom; call its left leg x.

Then the big tra pezoid which includes the shaded part has area

(1/2)((14 + x) + 26)(15)

and the bottom right triangle has area

(1/2)x(15)

and white triangle on the right has

(1/2)(26)(15 - 6)

The total area of the shared part is thus

(1/2)((14 + x) + 26)(15) - (1/2)x(15) - (1/2)(26)(15 - 6)

= (1/2)(15)(40 + x - x) - 13(9)

= 183

Answer: 183 sq in

8. That's an annulus, the difference between two circles. The outer one has radius 21/2 m, the inner one radius 21/2 - 3.5.

A = πR²-πr² = π( (21/2)² - (21/2 - 3.5)² ) = π(2(21/2)(3.5) - 3.5²) = 3.5π(21-3.5)=61.25π

Answer: 61.25π sq m

9. That looks like a parallelogram less a right triangle.

The parallelogram has area 15(23.8)

The right triangle missing leg x satisfies

x² + 21² = 23.8²

x = 11.2

The right triangle area is

(1/2) (21)(11.2)

So the shaded area is

15(23.8) - (1/2) (21)(11.2) =239.4

Answer: 239.4 sq ft

10. That's a circle less a square. The diagonal of the square is 8√2 and the radius of the square is half of that, 4√2

The area is

π(4√2)² - 8² = 32 π - 64

Answer: 32π - 64 sq cm

8 0

3 years ago

Use matrices to solve the system of equations if possible. Use Gaussian elimination with back substitution or gauss Jordan elimi

CaHeK987 [17]

In matrix form, the system is given by

$\begin{bmatrix} -1 & 1 & -1 \\ 2 & -1 & 1 \\ 3 & 2 & 1 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} -20 \\ 29 \\ 29 \end{bmatrix}$

I'll use G-J elimination. Consider the augmented matrix

$\left[ \begin{array}{ccc|c} -1 & 1 & -1 & -20 \\ 2 & -1 & 1 & 29 \\ 3 & 2 & 1 & 29 \end{array} \right]$

• Multiply through row 1 by -1.

$\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 2 & -1 & 1 & 29 \\ 3 & 2 & 1 & 29 \end{array} \right]$

• Eliminate the entries in the first column of the second and third rows. Combine -2 (row 1) with row 2, and -3 (row 1) with row 3.

$\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 5 & -2 & -31 \end{array} \right]$

• Eliminate the entry in the second column of the third row. Combine -5 (row 2) with row 3.

$\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 0 & 3 & 24 \end{array} \right]$

• Multiply row 3 by 1/3.

$\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 0 & 1 & 8 \end{array} \right]$

• Eliminate the entry in the third column of the second row. Combine row 2 with row 3.

$\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & 0 & -3 \\ 0 & 0 & 1 & 8 \end{array} \right]$

• Eliminate the entries in the second and third columns of the first row. Combine row 1 with row 2 and -1 (row 3).

$\left[ \begin{array}{ccc|c} 1 & 0 & 0 & 9 \\ 0 & 1 & 0 & -3 \\ 0 & 0 & 1 & 8 \end{array} \right]$

Then the solution to the system is

$\boxed{x=9, y=-3, z=8}$

If you want to use G elimination and substitution, you'd stop at the step with the augmented matrix

$\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 0 & 1 & 8 \end{array} \right]$

The third row tells us that $z=8$ . Then in the second row,

$y-z = -11 \implies y=-11 + 8 = -3$

and in the first row,

$x-y+z=20 \implies x=20 + (-3) - 8 = 9$

5 0

2 years ago

What is 0.96 rounded to the neatest tenth.

Alona [7]

Answer:

1.0

Step-by-step explanation:

6 is greater than 5 therefore it rounds 9 up to the next number which is 10, 1.0 or just 1.

4 0

3 years ago

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lesantik [10]

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2 years ago

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