The nth term is
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
r=2
the sum of a geometric seequence is
a1=1
r=2
we want to find
(since we minus 1, the highest exponet is 9 so add 1 to make it correct)
Answer:
The inverse for log₂(x) + 2 is - log₂x + 2.
Step-by-step explanation:
Given that
f(x) = log₂(x) + 2
Now to find the inverse of any function we put we replace x by 1/x.
f(x) = log₂(x) + 2
f(1/x) =g(x)= log₂(1/x) + 2
As we know that
log₂(a/b) = log₂a - log₂b
g(x) = log₂1 - log₂x + 2
We know that log₂1 = 0
g(x) = 0 - log₂x + 2
g(x) = - log₂x + 2
So the inverse for log₂(x) + 2 is - log₂x + 2.
X=25 and y=-2 so then y=-40 and x=? you will have to divide and and multiple and the answer will be x=500
Answer:
7
Step-by-step explanation:
The initial value is another name for the y-intercept. This equation is written in point slope form (y=mx+b). And before you think y-intercept means y, right? No that is incorrect, I got that wrong in the beginning too ;)
y=mx+b
y=8x+7
b in the point slope form equation is always the initial value or y-intercept or whatever people call it. So what substitutes b out here? 7. So 7 is the initial value!
:) Hope you understand now! Have a good day!
