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ohaa [14]
4 years ago
13

46.The function f graphed above is the function f(x) = log2(x) + 2 for x > 0. Find a formula for the inverse of this function

.
Mathematics
1 answer:
pantera1 [17]4 years ago
3 0

Answer:

The inverse for log₂(x) + 2  is - log₂x + 2.

Step-by-step explanation:

Given that

f(x) = log₂(x) + 2

Now to find the inverse of any function we put we replace x by 1/x.

f(x) = log₂(x) + 2

f(1/x) =g(x)= log₂(1/x) + 2

As we know that

log₂(a/b) = log₂a - log₂b

g(x) = log₂1 - log₂x + 2

We know that  log₂1 = 0

g(x) = 0 - log₂x + 2

g(x) =  - log₂x + 2

So the inverse for log₂(x) + 2  is - log₂x + 2.

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Simplify 2^2[4+(3-6)^2]-13
HACTEHA [7]

Answer:

It's 19.

Step-by-step explanation:

Use order of operations (PEMDAS):

2^2[4+(3-6)^2]-13

Parentheses first:

= 2^2[4 + (-2)^2] - 13

= 2^2 ( 4 + 4) - 13

=  2^2 * 8 - 13

Now work out the exponent:

= 4*8 - 13

Now the multiplication:

= 32 - 13

= 19.

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3 years ago
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The rule for this rotation is (x, y) converted into (-y, x). So, to find the answer you would make the y negative and switch the values in the ordered pair. A would be (3, -2), B would be (3, -5), and C would be (2, -4). So, your answer would be B. Hope this helps!
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Black_prince [1.1K]

Answer:

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Step-by-step explanation:

Given:

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Here we are required to find

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So 5.48 we have z = -2.714  and 5.82 we have  z = 2.143

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P( -2,714 < z < 2.143)

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