Answer:
4032 different tickets are possible.
Step-by-step explanation:
Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.
To find : How many different tickets are possible ?
Solution :
In the first race there are 9 ways to pick the winner for first and second place.
Number of ways for first place - 
Number of ways for second place - 
In the second race there are 8 ways to pick the winner for first and second place.
Number of ways for first place - 
Number of ways for second place - 
Total number of different tickets are possible is


Therefore, 4032 different tickets are possible.
Well sense it more pink it’s obviously gonna be a pink marble wit draw from it so p is possibly 23%
Answer:
7
Step-by-step explanation:
I don't completely understand what you were asking, but if you were counting by 7's, 91 would be after 84 instead of just 90.
Answer:
3.5568743e+14
Step-by-step explanation:
This is probabilities and you need to find the total possible outcomes
6+5+4= 17
So you do 17 factorials which basically is-multiplying each number down so 17 x 16 x 15 x14... and so on. So 17 factorial would get the total possible outcomes.