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3 years ago

Someone please help ASAP!!!!! SERIOUS ANSWERS ONLY!!!!!!

Mathematics

1 answer:

Kisachek [45]3 years ago

3 0

Y=mx+b

m=slope

the greater m is the steeper the graph

so the correct answer is B

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A ball is thrown vertically upwards from the ground. It rises to a height of 10m and then falls and bounces. After each bounce,

Citrus2011 [14]

${\huge{\fcolorbox{yellow}{red}{\orange{\boxed{\boxed{\boxed{\boxed{\underbrace{\overbrace{\mathfrak{\pink{\fcolorbox{green}{blue}{Answer}}}}}}}}}}}}}$

(i)

$\sf{a_n = 20 \times {( \frac{2}{3} )}^{n - 1} }$

(ii)

$\sf S_n = 60 \{1 - { \frac{2}{3}}^{n} \}$

Step-by-step explanation:

$\underline\red{\textsf{Given :-}}$

height of ball (a) = 10m

fraction of height decreases by each bounce (r) = 2/3

$\underline\pink{\textsf{Solution :-}}$

(i) We will use here geometric progression formula to find height an times

${\blue{\sf{a_n = a {r}^{n - 1} }}} \\ \sf{a_n = 20 \times { \frac{2}{3} }^{n - 1} }$

(ii) here we will use the sum formula of geometric progression for finding the total nth impact

$\orange {\sf{S_n = a \times \frac{(1 - {r}^{n} )}{1 - r} }} \\ \sf S_n = 20 \times \frac{1 - ( { \frac{2}{3} })^{n} }{1 - \frac{2}{3} } \\ \sf S_n = 20 \times \frac{1 - {( \frac{2}{3}) }^{n} }{ \frac{1}{3} } \\ \sf S_n = 3 \times 20 \times \{1 - ( { \frac{2}{3}) }^{n} \} \\ \purple{\sf S_n = 60 \{1 - { \frac{2}{3} }^{n} \}}$

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2 years ago

What is this? I don't freaking eat it

Contact [7]

Eat what exactly? and the attachment wont load.

7 0

3 years ago

Read 2 more answers

7/12 + 3/4 in simplest form?

Mariulka [41]

Well first we have to add 7/12 and 3/4 together which is 7/12+3/4=4/3. Now we have to reduce that to simplest form. Which would be 1 1/3 is 7/12+3/4 in simplest form!

4 0

3 years ago

Read 2 more answers

Need help solving this question please.

jok3333 [9.3K]

Answer: b) they loaded 112356 lbs of cargo

Step-by-step explanation:

When a boat or an object floats in water, the volume of water that it displaces is equivalent to its weight.

When moving into the port, the cargo boat displaced 2200 ft³ of water. Since the density of water is 62.42 lb/ft³ and mass = density × volume, then the mass of the cargo boat on entering the port is

2200 × 62.42 = 137324 lbs

On leaving the port, it displaces 4000 ft³ of water. The mass of the cargo boat on leaving the port is

4000 × 62.42 = 249680 lbs

The difference in both masses is

249680 - 137324 = 112356 lbs

Therefore, they loaded 112356 lbs of cargo

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3 years ago

What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?

DENIUS [597]

Answer:

i. 9