The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
<h3>How to find the derivative of a quadratic equation by definition of derivative</h3>
In this question we have a quadratic function, in which we must make use of the definition of derivative to find the expression of its first derivative. Then, the procedure is shown below:
f(x) = x² - 5 Given
f' = [(x + h)² - 5 - x² + 5] / h Definition of derivative
(x² + 2 · x · h + h² - 5 - x² + 5) / h Perfect square trinomial
(2 · x · h + h²) / h Associative, commutative and modulative properties / Existence of additive inverse
2 · x + h Distributive, commutative and associative properties / Definition of division / Existence of multiplicative inverse
2 · x h = 0 / Result
The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
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Answer:
27.8
Step-by-step explanation:
You need to do brackets first
3.6-1.8 = 1.8
Then substitute
4.5 x 8- (0.4 + 9.6- 1.8)
0.4+9.6-1.8=8.2
4.5 x 8 - 8.2 =27.8
Using exponential function concepts, it is found that the second function has a greater rate, as 0.8 > 0.2.
<h3>What is an exponential function?</h3>
It is modeled by:

In which:
- a is the initial value, that is, y when x = 0.
- b is the rate of change, as a decimal.
Function 1 is given by:

Hence the rate is b = 0.2.
Considering the values on the table, function 2 is given by:

Hence the rate is b = 0.8.
Hence, the second function has a greater rate, as 0.8 > 0.2.
More can be learned about exponential function concepts at brainly.com/question/14398287
Answer:
A
Step-by-step explanation:
Answer:
Yes
Step-by-step explanation:
10(49-49)
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2(7)(7^2-16)(7+3)
0
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4620
answer is 0