Answer:
(11/4) is the slope
Step-by-step explanation:
1) Subtract the second y value (-9) by the first y value (2) in the coordinates. This equals 11.
2) Then, subtract the second x value (-3) by the first x value (1) in the coordinates. This equals 4.
3) Divide the answer you get for step one by the answer for step 2 and that's your slope. 11/4
Answer: c. elm
Step-by-step explanation:
Given : The circumference of the oak tree= 0.539 meters
=
[∵ 1 m = 100 cm] (1)
The circumference of the ash tree= 0.509 yards
[∵ 1 yard = 3 feet]
[∵ 1 foot = 30.48 cm]
(2)
The circumference of the elm tree = 6281.70 millimeters
(3)
The circumference of the poplar tree = 0.000385 miles
[∵ 1 mile = 5280 feet]
[∵ 1 foot = 30.48 cm]
(4)
From (1) , (2) , (3 ) and (4) it is clear that
46.54< 53.9 < 61.96 < 628.17
Hence, the elm tree has the greatest circumference.
Ok she would have to buy 5 personal trainers to be equal the same with the other gym.
Gym 1 is $25 ( $25, $50, $75, $100)
Gym 2 is $15 ( $15, $30, $45,$60, $75)
$75 is are match
Answer:
1 And 3
Step-by-step explanation:
Answer:
The probability is ![P(0.35](https://tex.z-dn.net/?f=P%280.35%20%3CX%20%20%3C%200.55%29%20%3D%200.9921772)
Step-by-step explanation:
From the question we are told that
The sample size is n = 175
The population proportion is p = 0.45
Generally the mean of the sampling distribution is ![\mu_{x} = 0.45](https://tex.z-dn.net/?f=%5Cmu_%7Bx%7D%20%3D%20%200.45)
Generally the standard deviation is mathematically represented as
![\sigma_{x} = \sqrt{\frac{p (1-p)}{n} }](https://tex.z-dn.net/?f=%5Csigma_%7Bx%7D%20%3D%20%20%5Csqrt%7B%5Cfrac%7Bp%20%281-p%29%7D%7Bn%7D%20%7D)
=> ![\sigma_{x} = \sqrt{\frac{0.45 (1-0.45)}{175} }](https://tex.z-dn.net/?f=%5Csigma_%7Bx%7D%20%3D%20%20%5Csqrt%7B%5Cfrac%7B0.45%20%281-0.45%29%7D%7B175%7D%20%7D)
=> ![\sigma_{x} = 0.0376](https://tex.z-dn.net/?f=%5Csigma_%7Bx%7D%20%3D%200.0376)
Generally the probability of that the sample proportion of orange candies will be between 0.35 and 0.55 is
![P(0.35 < X < 0.55) = P( \frac{0.35 - 0.45}{0.0376} < \frac{X -\mu_{x}}{\sigma_{x}} < \frac{0.55 - 0.45}{0.0376} )](https://tex.z-dn.net/?f=P%280.35%20%3C%20%20X%20%3C%200.55%29%20%3D%20%20P%28%20%5Cfrac%7B0.35%20-%200.45%7D%7B0.0376%7D%20%3C%20%20%5Cfrac%7BX%20-%5Cmu_%7Bx%7D%7D%7B%5Csigma_%7Bx%7D%7D%20%20%3C%20%20%5Cfrac%7B0.55%20-%200.45%7D%7B0.0376%7D%20%29)
=> ![P(0.35](https://tex.z-dn.net/?f=P%280.35%20%3CX%20%20%3C%200.55%29%20%3D%20%20P%28%20-2.696%20%20%3C%20%20%5Cfrac%7BX%20-%5Cmu_%7Bx%7D%7D%7B%5Csigma_%7Bx%7D%7D%20%20%3C%202.6595%20%29)
Generally ![\frac{X - \mu_{x}}{\sigma_{x}} = Z (The \ standardized \ value \ of X)](https://tex.z-dn.net/?f=%5Cfrac%7BX%20-%20%5Cmu_%7Bx%7D%7D%7B%5Csigma_%7Bx%7D%7D%20%20%3D%20%20Z%20%20%28The%20%5C%20%20standardized%20%5C%20%20value%20%5C%20%20of%20%20X%29)
So
![P(0.35](https://tex.z-dn.net/?f=P%280.35%20%3CX%20%20%3C%200.55%29%20%3D%20%20P%28%20-2.6596%20%20%3C%20%20Z%3C%202.6595%20%29)
=> ![P(0.35](https://tex.z-dn.net/?f=P%280.35%20%3CX%20%20%3C%200.55%29%20%3DP%28%20%20Z%3C%202.6595%20%29%20-%20%20%20P%28%20Z%20%3C%20%20-2.6596%20%29)
From the z-table
![P( Z< 2.6595 ) = 0.99609](https://tex.z-dn.net/?f=P%28%20%20Z%3C%202.6595%20%29%20%3D%200.99609)
and
![P( Z< - 2.6595 ) = 0.0039128](https://tex.z-dn.net/?f=P%28%20%20Z%3C%20-%202.6595%20%29%20%3D%200.0039128)
So
![P(0.35](https://tex.z-dn.net/?f=P%280.35%20%3CX%20%20%3C%200.55%29%20%3D0.99609%20-%20%20%200.0039128)
=> ![P(0.35](https://tex.z-dn.net/?f=P%280.35%20%3CX%20%20%3C%200.55%29%20%3D%200.9921772)