Using pythag a^2+b^2=16^2
16^2=256
and since a=b the equation is 2x^2=256
/ each side by 2
x^2=128
x=sq rt of 128=11.31 roughly
Answer first number = 57 second number = 41
x= 16 + y
x + 2y = 139
16+ y + 2y =139
16 + 3y =139
16-16 +3y = 139-16
3y = 123
3/3y = 123/3
y= 41
x= 16+y
x = 16+41
x= 57