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slavikrds [6]
3 years ago
13

A student put $1,200 in a savings account paying simple interest of 4.5% per year. Find the total amount of the student's saving

s after 5 years. A: $700. B: $1470. C: $1000. D: $400​
Mathematics
1 answer:
WINSTONCH [101]3 years ago
3 0

Answer:

(B) $1470

Step-by-step explanation:

Given that the principal initial amount, p=$1200

Rate of simple interest per year, r=4.5% = 0.045

Time, t=5 years

Interest after 5 years,

I=prt= 1200 x 0.045 x 5 = 270

Total amount = Principal initial amount + Interest

=1200+270=1470

So, the total amount of the student's savings after 5 years is $1470.

Hence, option (B) is correct.

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What’s the product of....<br><br> (0.25)•(1.4)=
wolverine [178]

Answer:

0.35

Step-by-step explanation:

0.25 × 1.4 =

0.25×100=25

1.4 × 10 = 14

25×10=250

25×4=100

250+100=350

25×14=350

350÷1000(0.25》25, 1.4》14)

0.35

4 0
3 years ago
Jill calls a plumber to her house to fix the leaking faucets . The plumber charges a one-time fee of $50 plus an additional $35
Anton [14]

Answer:

independent=$50

dependent=$35X

Step-by-step explanation:

50 is the independent variable because it doesn't change.

35X is the dependent variable because it does change.

8 0
3 years ago
Find the sum of the convergent series 7 0.7 0.007
mafiozo [28]
7+0.7+0.007+\cdots=7\left(1+\dfrac1{10}+\dfrac1{100}+\cdots\right)

Let S_n denote the nth partial sum of the series, i.e.

S_n=1+\dfrac1{10}+\dfrac1{100}+\cdots+\dfrac1{100^n}

Then

\dfrac1{10}S_n=\dfrac1{10}+\dfrac1{100}+\dfrac1{1000}+\dfrac1{10^{n+1}}

and subtracting from S_n we get

S_n-\dfrac1{10}S_n=\dfrac9{10}S_n=1-\dfrac1{10^{n+1}}
\implies S_n=\dfrac{10}9\left(1-\dfrac1{10^{n+1}}\right)

As n\to\infty, the exponential term vanishes, leaving us with

\displaystyle\lim_{n\to\infty}S_n=\dfrac{10}9

and so

7+0.7+0.007+\cdots=7.777\ldots=\dfrac{70}9
3 0
3 years ago
What is the value of -16?<br> A. -4<br> B. -4i<br> C. 4i<br> D. 4;2
hammer [34]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the sum and difference (first mixed number minus the second mixed number) for the following pair of mixed numbers. The answ
xz_007 [3.2K]

Answer:

Sum = 15 8/15, Difference = 1 2/15

Step-by-step explanation:

8⅓, 71/5

A. Sum

8⅓ + 7 1/5

Convert to improper fraction

25/3 + 36/5

Find the LCM of 3 and 5. The result is 15. Divide 15 by the denominator of each fraction and multiply the result obtained with the numerator. The result is shown below:

[(25×5) + (36×3)] / 15

[125 + 108] / 15

233 / 15

Convert to mixed fraction

15 8/15

B. Difference

8⅓ – 7 1/5

Convert to improper fraction

25/3 – 36/5

Find the LCM of 3 and 5. The result is 15. Divide 15 by the denominator of each fraction and multiply the result obtained with the numerator. The result is shown below:

[(25×5) – (36×3)] / 15

[125 – 108] / 15

17 / 15

Convert to mixed fraction

1 2/15

SUMMARY:

Sum = 15 8/15, Difference = 1 2/15

3 0
3 years ago
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