Hey ! there
Answer:
- <u>1</u><u>1</u><u>3</u><u>.</u><u>0</u><u>4</u><u> </u><u>unit </u><u>cube</u>
Step-by-step explanation:
In this question we are provided with a sphere <u>having</u><u> </u><u>radius </u><u>3 </u><u>units </u>and <u>value </u><u>of </u><u>π </u><u>is </u><u>3.</u><u>1</u><u>4</u><u> </u><u>.</u><u> </u>And we're asked to find the<u> </u><u>volume</u><u> of</u><u> </u><u>sphere</u><u> </u><u>.</u>
For finding volume of sphere , we need to know its formula . So ,

<u>Where</u><u> </u><u>,</u>
- π refers to <u>3.</u><u>1</u><u>4</u>
- r refers to <u>radius</u><u> of</u><u> sphere</u>
<u>Sol</u><u>u</u><u>tion </u><u>:</u><u> </u><u>-</u>
Now , we are substituting value of π and radius in the formula ,

Simplifying it ,

Cancelling 3 with 3 :

We get ,

Multiplying 4 and 3.14 :

Multiplying 12.56 and 9 :

- <u>Henceforth</u><u> </u><u>,</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>sphere</u><u> </u><u>having </u><u>radius </u><u>3 </u><u>units </u><u>is </u><em><u>1</u></em><em><u>1</u></em><em><u>3</u></em><em><u> </u></em><em><u>.</u></em><em><u>0</u></em><em><u>4</u></em><em><u> </u></em><em><u>units </u></em><em><u>cube </u></em><em><u>.</u></em>
<h2>
<u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
Let i = sqrt(-1) which is the conventional notation to set up an imaginary number
The idea is to break up the radicand, aka stuff under the square root, to simplify
sqrt(-8) = sqrt(-1*4*2)
sqrt(-8) = sqrt(-1)*sqrt(4)*sqrt(2)
sqrt(-8) = i*2*sqrt(2)
sqrt(-8) = 2i*sqrt(2)
<h3>Answer is choice A</h3>
According to the normal distribution curve:
<span>"the percent of women whose heights are between 64 and 69.5 inches"</span> represents the values within 2 standard deviation ,,,
And that value is 95% of the whole data
Answer: P=47 inches
Step-by-step explanation:
First, you have to find the other side lengths. Two of the sides are equal to 20 because this is a rectangle. The first blank would be 20 because 20 times the other side length is equal to 70. Then you would divide 70 by 20 which would equal x. x would equal 3.5 in. Then the perimeter would be:
2(20)+2(3.5)=P
P=47 inches
Answer:
x + 29 = 41
Step-by-step explanation:
Trevon received some money, but we don't know how much, so we will represent that with x.
The money he received will be add the amount he had last friday, $29.
The equation will equal his current amount, $41.