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nalin [4]
3 years ago
6

Need help Please…………….

Mathematics
1 answer:
eduard3 years ago
6 0
Answer:

B IS a subset of set A because every element of set B is contained in set A
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If MP=6x-5,QR=3x+1, and RN=6, what is QN
stepan [7]

Answer:

12

Step-by-step explanation:

12

7 0
2 years ago
A segment has one endpoint at (-4,1) and it's midpoint at (3,0). What is the x-coordinate of the other endpoint?
nikklg [1K]

Answer:

(10; -1)

the x-coordinate of the other endpoint is (x;y)

because the segment has midpoint at (3;0)

=> x - 4 = 3.2 = 6

y + 1 = 0.2 = 0

<=> x = 10

y = -1

=> the other endpoint is (10; -1)

5 0
2 years ago
Read 2 more answers
$1000 is invested at 2.9% annual interest for 6 months.<br> a. Simple Interest b. Compound Interest
kirza4 [7]

Answer:

a. Simple interest = $174

b. Compund interest = $1187.1

Step-by-step explanation:

Given the following data;

Principal, P = $1000

Interest, R = 2.9%

Time, T = 6 months

a. To find the simple interest;

S.I = (PRT)/100

S.I = (1000*2.9*6)/100

S.I = 17400/100

S.I = $174

b. To find the compound interest;

A = P(1 + \frac{r}{100})^{t}

Substituting into the formula, we have;

A = 1000(1 + \frac{2.9}{100})^{6}

A = 1000(1 + 0.029)^{6}

A = 1000(1.029)^{6}

A = 1000(1.1871)

A = $1187.1

8 0
3 years ago
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
if the focus of an ellipse are (-4,4) and (6,4), then the coordinates of the enter of the ellipsis are
STALIN [3.7K]
I’m sorry but I literally dunno
6 0
3 years ago
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