Drag and drop the symbols to enter the equation of the circle in standard form with center and radius given. Center (8, 0), radi
us = sqrt 3
1 answer:
We know that
<span>the equation of the circle in standard form is
(x-h)</span>²+(y-k)²=r²
where
(h,k) is the center of the circle
and
r is the radius
in this problem
(h,k) is <span>(8, 0)
and radius r=</span>√3 units
so
(x-h)²+(y-k)²=r²-----> (x-8)²+(y-0)²=(√3)²---->(x-8)²+y²=3
the answer is
(x-8)²+y²=3
see the attached figure
<span>the equation of the circle in standard form is
(x-h)</span>²+(y-k)²=r²
where
(h,k) is the center of the circle
and
r is the radius
in this problem
(h,k) is <span>(8, 0)
and radius r=</span>√3 units
so
(x-h)²+(y-k)²=r²-----> (x-8)²+(y-0)²=(√3)²---->(x-8)²+y²=3
the answer is
(x-8)²+y²=3
see the attached figure
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