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sammy [17]
3 years ago
13

Please help (Proportions)

Mathematics
2 answers:
Yanka [14]3 years ago
6 0

Answer:

1 cup of sugar ..............

In-s [12.5K]3 years ago
4 0
ANSWER: 1 cup

36 cookies: 2 cups
18 cookies: 1 cup
(Divided by 2)
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Rita bought 4 CDs that were each the same price. Including sales tax, she paid a total of $ 61.60. Of that total,$ 2.80 was tax.
kirill115 [55]

Answer:

The price of each CD is:

$14.70

Step-by-step explanation:

(61.6 - 2.8) /4

=  58.8/4

= $14.7

4 0
3 years ago
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Find all solutions for the absolute value equation |2x - 3| = x + 3.
Fed [463]
1.\\2x-3=x+3\\\\x=6\\\\2.\\3-2x=x+3\\\\3x=0\\\\x=0\\\\x\in\{0,6\}
7 0
3 years ago
I would like to know if 1 km is greater or less then 999 m
aleksandrvk [35]
Greater 1 km = 1000 m
so it's greater than 999 m
7 0
3 years ago
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The diameter of a road roller is 90 cm and is 2m 10 cm in length. If it takes 400 revolutions to level a playground, find the co
Over [174]

Answer:

The cost of   leveling the ground is  Rs 5340.6

Step-by-step explanation:

Given:

Diameter of the road roller =  90 cm

Length of the road roller = 2m 10 cm

Total number of number of revolution = 400

Cost of leveling = Rs 2.25 per square meter

To Find:

Total cost of leveling the ground  = ?

Solution:

Step 1 : Finding the surface area of the road roller

Converting  cm to m

90 cm  = 0.9 m

2m 10 cm  = 2 + 0.1 m = 2.1 m

Surface area of the road roller = surface are of the cylinder

= 2\pi r h

r= radius of the road roller

r= \frac{0.9}{2}

r=0.45

Now surface area  is

=>2 \times \pi \times 0.45 \times

=>6.28 \times 0.45 \times 2.1

=>2.826 \times 2.1

=>5.934

Step 2 : Finding the area of  the ground

Total area of the ground = Surface area  of the road roller X number of revolutions  

=>5.934 \times 400

=> 2373.6

Step 3 : Finding the  cost of leveling

Total cost of leveling =  area of the ground  X  Cost per square meter

=> 2373.6\times 2.25

=>5340.6

4 0
3 years ago
Which measure would be the most appropriate to describe the center of the data in the histogram below? A-mean B-range C-median D
S_A_V [24]

The center of data of histogram is the median and/or mean of the data.The center of a distribution is the middle of any data.

when the data is skewed, the median is more appropriate to use as the measure of a typical value.

Mean is used as the measure of center  when the data is  symmetric.

In the given Histogram the data is skewed and so Median describe the center of the data in the histogram.

Option C- median is the right answer.

5 0
3 years ago
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