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zmey [24]
3 years ago
9

Plzzz help me km doing a test​

Mathematics
1 answer:
Bess [88]3 years ago
5 0

Answer: 5.5

Step-by-step explanation: if you divided 11 by 2 you will get the miles to hour

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Write the equation of a line that is perpendicular to y=0.25x-7y=0.25x−7y, equals, 0, point, 25, x, minus, 7 and that passes thr
Digiron [165]

Given equation of line y=0.25x-7.

On comparing given equation with slope-intercept form y=mx+b.

We get m=0.25.

0.25 could be written 25/100 in simplest fractions 1/4.

Line are perpendicular.

Therefore, slope of the perpendiular line would be reciprocal and opposite in sign of the given slope of the line.

Reciprocal of 1/4 is 4 and opposite of sign of 4 would be -4.

So, the slope of the required line is m=-4.

We are given a point (-6,8).

Applying point-slope form, we get

y-y1=m(x-x1)

y-8 = -4(x- (-6))

y-8 = -4(x+6)

y-8 = -4x -24.

Adding 8 on both sides, we get

y-8=8 = -4x -24+8

y=-4x-16.

Therefore, the equation y=-4x-16 is perpendicular to the given eqution of line.

8 0
3 years ago
I will give brainliest
ioda

Answer:

2,-5,-12,-19,-26

Step-by-step explanation:

-7n +9

-7(1) +9 = 2

-7(2)+ 9= -5

-7(3)+9 = -12

-7(4)+9 = -19

-7(5)+9 = -26

7 0
2 years ago
I NEED HELPPP ASAP pleaseeeeeee
Komok [63]

Answer:

Subtract 23 from both sides

Step-by-step explanation:

This is how algebra works, to get a variable by itself you have to do the opposite to both sides. Hope this helped.

5 0
3 years ago
Read 2 more answers
a discounted concert ticket costs $14.50 less than the original price p.You pay $53 for a discounted ticket.Write an equation th
Ahat [919]

Answer:

$53.00 + $14.50

= 67.50

Make sure to leave a good review if it helped you

-Adan


7 0
4 years ago
Someone pls help me out
Firlakuza [10]

Answer:

D.

Step-by-step explanation:

A student Loan is NOT and asset.  An asset means "Property or something that you own." You do not OWN a student loan. you have to borrow it and pay it back.

Hope this helps! Please mark as brainliest! Thanks!

4 0
4 years ago
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