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Andreyy89
3 years ago
11

I NEED HELPPP ASAP pleaseeeeeee

Mathematics
2 answers:
Komok [63]3 years ago
5 0

Answer:

Subtract 23 from both sides

Step-by-step explanation:

This is how algebra works, to get a variable by itself you have to do the opposite to both sides. Hope this helped.

maw [93]3 years ago
4 0

Answer:

It's D: subtract 23 from both sides of the equation because inverse operations  

Step-by-step explanation:

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Is the square root of 42.25​
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Y = –A system of equations. y equals negative StartFraction one-half EndFraction x plus 4. x plus 2 y equals negative 8.x + 4
laila [671]

Y = -1/2x + 4

X + 2y = -8

Replace y in the second equation with the first one:

X + 2(-1/2x +4)=-8

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One day, he bought 10 pairs of socks for $2.50 each and 3 pairs of shoes for dollars each. He
IrinaVladis [17]

Answer:

2.50(10) + 3x = 135.97, x = 38.66

Step-by-step explanation:

This should be pretty simple.

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Our total is 135.97 though-

so here, we take our total from the right side of the equation, and subtract 25 from that.

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5 0
3 years ago
Determine whether each of the following functions is a solution of laplace's equation uxx uyy = 0.
ratelena [41]

Both functions are the solution to the given Laplace solution.

Given Laplace's equation: u_{x x}+u_{y y}=0

  • We must determine whether a given function is the solution to a given Laplace equation.
  • If a function is a solution to a given Laplace's equation, it satisfies the solution.

(1) u=e^{-x} \cos y-e^{-y} \cos x

Differentiate with respect to x as follows:

u_x=-e^{-x} \cos y+e^{-y} \sin x\\u_{x x}=e^{-x} \cos y+e^{-y} \cos x

Differentiate with respect to y as follows:

u_{x x}=e^{-x} \cos y+e^{-y} \cos x\\u_{y y}=-e^{-x} \cos y-e^{-y} \cos x

Supplement the values in the given Laplace equation.

e^{-x} \cos y+e^{-y} \cos x-e^{-x} \cos y-e^{-y} \cos x=0

The given function in this case is the solution to the given Laplace equation.

(2) u=\sin x \cosh y+\cos x \sinh y

Differentiate with respect to x as follows:

u_x=\cos x \cosh y-\sin x \sinh y\\u_{x x}=-\sin x \cosh y-\cos x \sinh y

Differentiate with respect to y as follows:

u_y=\sin x \sinh y+\cos x \cosh y\\u_{y y}=\sin x \cosh y+\cos x \sinh y

Substitute the values to obtain:

-\sin x \cosh y-\cos x \sinh y+\sin x \cosh y+\cos x \sinh y=0
The given function in this case is the solution to the given Laplace equation.

Therefore, both functions are the solution to the given Laplace solution.

Know more about Laplace's equation here:

brainly.com/question/14040033

#SPJ4

The correct question is given below:
Determine whether each of the following functions is a solution of Laplace's equation uxx + uyy = 0. (Select all that apply.) u = e^(−x) cos(y) − e^(−y) cos(x) u = sin(x) cosh(y) + cos(x) sinh(y)

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2 years ago
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