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Flauer [41]
2 years ago
6

What's

" alt=" \sqrt{33 + 9 - 6} " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
valentina_108 [34]2 years ago
8 0
Okay solve what’s inside the root...

33+9-6 = 36

You would be left with root 36 but if you calculate the square root you’d get 6 because...

6•6 = 36


^ So, your answer is just 6
Veronika [31]2 years ago
8 0

Answer:

answer is '6'

Step-by-step explanation:

understand friend

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How many times does 0.6 go into 12.66?<br> first brainlyist
aleksklad [387]

Answer:

.6 goes into 12.66 21.1 times

8 0
3 years ago
Lines l and m are parallel.<br> Use the diagram to determine the measure of ∠3.
Pavlova-9 [17]

Answer:

∠3 is 70°

Step-by-step explanation:

∠1 is 50° since it is across from another 50° angle

and then you use the equation x+25+2x+50=180 to find x

x then equals 35°

you then use the alternate interior angle theorem to say that ∠3 is 2x, or 70°

5 0
2 years ago
Which expression has the greatest value when x=3
Luden [163]

Answer:

The third expression: (2x)^3

Step-by-step explanation:

Plug in 3 for x in each expression

2x^3

2(3)^3

Use PEMDAS

2 (3 × 3 × 3)

2 (9 × 3)

2 (27)

54

2x^3 + 5

(The last expression told us 2x^3 = 54 so feel free to use this information to make life easier)

54 + 5

59

(2x)^3

(2 × 3)^3

Use PEMDAS

6^3

6 × 6 × 6

36 × 6

216

(x - 1)^3

(3 - 1)^3

Use PEMDAS

2^3

2 × 2 × 2

4 × 2

8

216 is the greatest value so the third expression is the answer

7 0
2 years ago
Kendall's sister had 25 hair clips. 7 of them were blue and the rest were purple.What percent of Kendall's sister hair clips wer
Ludmilka [50]
The answer is 18/25 = .72 or 72%
3 0
2 years ago
The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
2 years ago
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