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3 years ago

7

Fill in the blanks, solve x2+6x +y2- 4y = 23

1 answer:

Aleks [24]3 years ago

6 0

Answer:

Step-by-step explanation:

See completed figure attached.

Note that some blanks are missing colours from the question.

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Scilla [17]

Here’s the work - answer is 0.833 mi

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3 years ago

Help me please?! I need help

Ipatiy [6.2K]

Answer:

7x + 2y = 9

Step-by-step explanation:

standard form is always written as:

Ax + By = C

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2 years ago

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please help 30 points !! in a proportional relationship when Y=2 when X=8 Which of the following equations would describe this r

Alex777 [14]

Answer:

(1)

Step-by-step explanation:

We will try:

(1) y = $\frac{1}{4}$ x => 2 = 2 (seems legit)

(2) y = 4x => 2 = 32 (nope)

(3) y = x - 6 => 2 = 2 (yes but actually no because it is proportional relationship)

(4) y = $\frac{1}{2}$ x - 2 => 2 = 2 (like the above)

8 0

3 years ago

Find each quotient. Write in simplest form. keep answer as fraction - not decimal

kirill [66]

So we are given the expression:

$\frac{mn^{2}}{4}$ ÷ $\frac{m^{2}n}{8}$

When we divide fractions, we must flip the second term and change the sign to multiplication:

$\frac{mn^{2}}{4} *\frac{8}{m^{2}n}$

And then we multiply across:

$\frac{mn^{2}}{4} *\frac{8}{m^{2}n}= \frac{8mn^{2}}{4m^{2}n}$

Then we can break apart all of the like variables for simplification:

$\frac{8mn^{2}}{4m^{2}n}=\frac{8}{4} * \frac{m}{m^{2}} *\frac{n^{2}}{n}$

When we simplify variables through division, we subtract the exponent of the numerator from the exponent of the denominator. So we then have:

$\frac{8}{4} =2$

$\frac{m}{m^{2}}=m^{-1} =\frac{1}{m}$

$\frac{n^{2}}{n}=n^{1}=\frac{n}{1}$

So then we multiply all of these simplified parts together:

$\frac{2}{1}*\frac{1}{m}*\frac{n}{1} =\frac{2n}{m}$

So now we know that the simplified form of the initial expression is: $\frac{2n}{m}$ .

3 0

2 years ago

Verify that (cos²a) (2 + tan² a) = 2 - sin² a....<br>

Sveta_85 [38]

Trigonometric Formula's:

$\boxed{\sf \ \sf \sin^2 \theta + \cos^2 \theta = 1}$

$\boxed{ \sf tan\theta = \frac{sin\theta}{cos\theta} }$

Given to verify the following:

$\bf (cos^2a) (2 + tan^2 a) = 2 - sin^2 a$

$\texttt{\underline{rewrite the equation}:}$

$\rightarrow \sf (cos^2a) (2 + \dfrac{sin^2 a}{cos^2 a} )$

$\texttt{\underline{apply distributive method}:}$

$\rightarrow \sf 2 (cos^2a) + (\dfrac{sin^2 a}{cos^2 a} ) (cos^2a)$

$\texttt{\underline{simplify the following}:}$

$\rightarrow \sf 2cos^2 a + sin^2 a$

$\texttt{\underline{rewrite the equation}:}$

$\rightarrow \sf 2(1 - sin^2a ) + sin^2 a$

$\texttt{\underline{distribute inside the parenthesis}:}$

$\rightarrow \sf 2 - 2sin^2a + sin^2 a$

$\texttt{\underline{simplify the following}} :$

$\rightarrow \sf 2 - sin^2a$

Hence, verified the trigonometric identity.

7 0

2 years ago

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