All categories

2 years ago

I need help with geometry

Mathematics

1 answer:

astra-53 [7]2 years ago

8 0

Answer:

Step-by-step explanation:

Use the Pythagorean theorem:

a^2 + b^2 = c^2
5^2 + 12^2 = c^2
25 + 144 = c^2
c^2 = 169
13

Note: This also happens to be a Pythagorean triple where all three numbers are integers. These can be memorized.

You might be interested in

Task: Volume & Surface Area

Triss [41]

Okay so starting off I get that this math can be really confusing but you’ll get it if you keep working at it. Don’t give up you got this. For part it it is asking for the volume in cubic feet to do this you multiple H•W•L

H=hight

W=Width

L=Length

Now you don’t really need to know exactly which side is the H,L, or W but since you only have 3 sides with domentions you know that you multiply all three sides now it doesn’t matter what order you do it in.

Please respond if this helped for part A. You got this keep your head up.

3 0

3 years ago

How is net pay different from gross pay?

Mekhanik [1.2K]

Answer:

Gross pay is the amount of money your employees receive before any taxes and deductions are taken out.

Net pay is the amount of money your employees take home after all deductions have been taken out.

Step-by-step explanation:

7 0

3 years ago

5/6+2 3/4 (it is a faction)

frosja888 [35]

Answer: the answer would be 3 7/12

Step-by-step explanation:

First you must find the common denominator(which is 12) and then add the fractions

4 0

3 years ago

An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s

Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, $s=120\ ft/s$

The height 'h' of the debris above the ground is given as:

$h(t)=-16t^2+120t$

As per question, $h(t)=56\ ft$ . Therefore,

$56=-16t^2+120t$

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

$-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0$

Using quadratic formula to solve for 't', we get:

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s$

Therefore, the debris will reach a height of 56 ft twice.

When time $t=0.5\ s$ during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at $t=7\ s$ , the height is 56 ft.

5 0

3 years ago

6+5(a-1)=36 please answer me

azamat

i think the answer is 35

6 0

3 years ago

Read 2 more answers