When two fractions have the same numerators
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Based on the data set, the variance for this sample of tests is 4
<h3>How to find the variance for this sample of tests?</h3>The sample of test is given as:
78, 79, 79, 81, and 83.
Calculate the mean, using:
Mean = Sum/Count
So, we have
Mean = (78 + 79 + 79 + 81 + 83)/5
Evaluate
Mean = 80
The variance is calculated as
This gives
= [(78 - 80)^2 + (79 - 80)^2 + (79- 80)^2 + (81- 80)^2 + (83- 80)^2)]/[5 - 1]
Evaluate the numerator and the denominator.
So, we have:
=16/4
Evaluate the quotient
= 4
Hence, the variance for this sample of tests is 4
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