I think your asking how much the school will have left over. If so:
125 ( not including the tickets)
It depends on how many kids are coming to the dance in order to fully solve this problem.
You didn't word this properly so that what I got with what I had:)
If you have anymore questions, ask me them on my profile so I'll be sure to get them:)
I hope this helps:)
It would be arrow
Because that is the right answer
Answer:
yes
Step-by-step explanation:
10:20=
5 times 2= 10
5 times 4= 20
2:4=
1 times 2=2
2 times 2= 4
1:2
Answer:
60 seconds, 7715 feet
Step-by-step explanation:
Plane A and B start out 615 feet apart, and we find this by subtracting the height of plane A from plane B, getting 5000-4385=615. Now we have to find how many more feet of altitude plane A is gaining per second over plane B.
To find this we subtract 45.25 from 55.5 and get 10.25 feet per second. Now to find out how many seconds until they'll be at the same altitude we simply divide 615 by 10.25, getting 60 seconds.
For the second part, to find the altitude at this point, we simply multiply the altitude gain of one of the planes per second by the time of 60 seconds to get how much altitude they gained over that time, and add it to the starting altitude. Doing this with plane B we get 45.25*60=2715, and we add that to 5000 to get the final answer of 7715.
