Answer:
a) 266 tubes , TC_r = $53.2
b) 266 tubes , T.Loss = $13.30
Step-by-step explanation:
Given:
- The sample size of tubes n = 1,000 tubes
- The mean of the sample u = 6.5 oz
- The standard deviation of the sample s.d = 0.8 oz
- Cost of manufacturing a tube C_t = 50 cents
- Cost of refilling a tube C_r = 20 cents
- Profit loss per tube Loss = 5 cents
Find:
a). How many tubes will be found to contain less than 6 ounces? In that case, what will be the total cost of the refill?
b) How many tubes will be found to contain more than 7 ounces? In that case, what will be the amount of profit lost?
Solution:
- First we will compute the probability of tube containing less than 6 oz.
- Declaring X : The amount of toothpaste.
Where, X ~ N ( 6.5 , 0.8 )
- We need to compute P ( X < 6 oz )?
Compute the Z-score value:
P ( X < 6 oz ) = P ( Z < (6 - 6.5) / 0.8 ) = P ( Z < -0.625 )
Use the Z table to find the probability:
P ( X < 6 oz ) = P ( Z < -0.625 ) = 0.266
- The probability that it lies below 6 ounces. The total sample size is n = 1000.
The number of tubes with X < 6 ounces = 1000* P ( X < 6 oz )
= 1000*0.266 = 266 tubes.
- The total cost of refill:
TC_r = C_f*(number of tubes with X < 6)
TC_r = 20*266 = 5320 cents = $53.2
- We need to compute P ( X > 7 oz )?
Compute the Z-score value:
P ( X > 7 oz ) = P ( Z > (7 - 6.5) / 0.8 ) = P ( Z < 0.625 )
Use the Z table to find the probability:
P ( X > 7 oz ) = P ( Z > 0.625 ) = 0.266
- The probability that it lies above 7 ounces. The total sample size is n = 1000.
The number of tubes with X > 7 ounces = 1000* P ( X > 7 oz )
= 1000*0.266 = 266 tubes.
- The total cost of refill:
T.Loss = Loss*(number of tubes with X > 7)
T.Loss = 5*266 = 1330 cents = $13.30
x 1 x 1 = 