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Makovka662 [10]
3 years ago
9

IN (3)

Mathematics
1 answer:
svetoff [14.1K]3 years ago
8 0

Answer:

(a) Rule: Multiply the input (x) by 2 and add 5 to the result of the product

(b) y  =2x +5

Step-by-step explanation:

Given

The attached table

Solving (a): The rule of the table in words

First, we calculate the slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

Using:

(x_1,y_1) =  (2,9)

(x_1,y_1) =  (10,25)

So, we have:

m = \frac{25 - 9}{10 - 2}

m = \frac{16}{8}

m=2

The equation is calculated using:

y - y_1 =m(x - x_1)

Using:

(x_1,y_1) = (6,17)

We have:

y - 17 =2(x - 6)

y - 17 =2x - 12

Make y the subject

y  =2x - 12+17

y  =2x +5

Hence, the rule is:

Multiply the input (x) by 2 and add 5 to the result of the product

(b): The rule, in algebra

As solved in (a), the rule is:

y  =2x +5

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If a substance decays at a rate of 25% every 10 years, how long will it take 512 grams of the substance to decay to 121.5 grams
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Answer:

It will take 50 years to decay from 512 grams to 121.5 grams.

Step-by-step explanation:

The decay formula :

N=N_0e^{-\lambda t}

where

N= amount of substance after t time

N₀= initial of substance

t= time.

A substance decays at a rate 25% every 10 years.

So, remaining amount of the substance is = (100%-25%)= 75%

\frac{N}{N_0}=\frac{75\%}{100\%}=\frac{75}{100}=\frac34, t= 10

N=N_0e^{-\lambda t}

\Rightarrow \frac {N}{N_0}=e^{-\lambda t}

\Rightarrow \frac34 =e^{-\lambda .10}

Taking ln both sides

\Rightarrow ln|\frac34| =ln|e^{-\lambda .10}|

\Rightarrow ln|\frac34|=-10\lambda

\Rightarrow \lambda=\frac{ ln|\frac34|}{-10}

Now , N₀= 512 grams, N= 121.5 grams, t=?

N=N_0e^{-\lambda t}

\therefore 121.5=512e^{-\frac{ln|\frac34|}{-10}.t}

\Rightarrow 121.5=512e^{\frac{ln|\frac34|}{10}.t}

\Rightarrow \frac{121.5}{512}=e^{\frac{ln|\frac34|}{10}.t}

Taking ln both sides

\Rightarrow ln|\frac{121.5}{512}|=ln|e^{\frac{ln|\frac34|}{10}.t}|

\Rightarrow ln|\frac{121.5}{512}|={\frac{ln|\frac34|}{10}.t}

\Rightarrow t=\frac{ln|\frac{121.5}{512}|}{\frac{ln|\frac34|}{10}}

\Rightarrow t=\frac{10.ln|\frac{121.5}{512}|}{{ln|\frac34|}}

⇒t=50 years

It will take 50 years to decay from 512 grams to 121.5 grams.

8 0
4 years ago
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