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3 years ago

Will mark you brainlest

Mathematics

1 answer:

Sergio039 [100]3 years ago

4 0

Answer:

0.046875

Step-by-step explanation:

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If y=(sec^-1x)^2, then show that x^2(x^2-1) d^2y/dx^2 + (2x^3 - x) dy/dx = 2

Arisa [49]

Step-by-step explanation:

Hope it helps you in your learning process.

8 0

3 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

3 years ago

|x |-8= -5 what's the answer

ladessa [460]

Answer:

|x |-7 = -5 ( x = -3 )

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A homeowner has 20 feet of fencing material to enclose a rectangular area for his pets. the rectangular area is adjacent to a ho

VikaD [51]

5X10=50 sq ft area
Around the 3 sides= 5+10+5=20

7 0

3 years ago

A store has a 40% off sale on headphones. With this discount, the price of one pair of headphones in $36. What is the original p

Mariana [72]

Let the original price of headphone = x

there is 40% discount which is 0.40x

so the payment price will be x-0.40x = 0.60x

Given that paid amount is $36

so both will be equal

0.60x = 36

x=36/0.60

x=60

Hence final answer is $60.

3 0

3 years ago

Read 2 more answers