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frozen [14]
3 years ago
7

C=(y-6)h solve for y

Mathematics
1 answer:
murzikaleks [220]3 years ago
6 0

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

Answer:y=c/h +6

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Find the solutions to 9x^2-54x=0
astra-53 [7]

Answer:

x₁ = 0

x₂ = 6

Step-by-step explanation:

9x² - 54x = 0

9x(x - 6) = 0

x(x - 6) = 0

x = 0

x - 6 = 0 → x = 6

Hope this helps! :)

7 0
3 years ago
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Each tape diagram represents I whole.
Monica [59]

Hi! From what I know, your answer should be 5n = 1.75.

This is because all 5 of those n's ultimately equal the large box of 1.75 on the top. Think of it as fractions. if we replaced 1.75 with 1, those n's would each be 1/5.

4 0
3 years ago
Which of the following statements is the contrapositive of "If I have money, then I spend it"?
Vika [28.1K]
Im looking towards B
4 0
3 years ago
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John has a boat that will travel at the rate of 15 kph in still water. He can go upstream for 35 km in the same time it takes to
Otrada [13]

Answer:

The boat traveling at 24 kph when John goes downstream.

Step-by-step explanation:

We are given the following in the question:

John has a boat that will travel at the rate of 15 kph in still water.

Let x be the speed of the current.

Speed of boat in upstream

(15-x)\text{ kph}

Speed of water in downstream

(15+x)\text{ kph}

Relation:

\text{Speed} = \dfrac{\text{Distance}}{\text{Time}}

We have to find the speed of boat in downstream.

Time to travel upstream for 35 km = Time to travel  140 km downstream

\displaystyle\frac{35}{15-x}=\frac{140}{15+x}\\\\35(15+x) = 140(15-x)\\525 + 35x = 2100 - 140x\\175x = 1575\\x = 9

Thus, speed of current is 9 kph.

Speed of boat in downstream = 15 + 9 = 24 kph.

Thus, the boat traveling at 24 kph when John goes downstream.

4 0
3 years ago
Question 1 of 10
Darya [45]

Answer:

Log₆ (A⁵C² / D⁶) = –13

Step-by-step explanation:

From the question given above,

Log₆ A = 1

Log₆ C = 3

Log₆ D = 4

Log₆ (A⁵C² / D⁶) =?

Recall:

Log MN / U = Log M + Log N – Log U

Therefore,

Log₆ (A⁵C² / D⁶) = Log₆ A⁵ + Log₆ C² – Log₆ D⁶

Recall:

Log Mⁿ = nLog M

Thus,

Log₆ A⁵ + Log₆ C² – Log₆ D⁶

= 5Log₆ A + 2Log₆ C – 6Log₆ D

Log₆ A = 1

Log₆ C = 3

Log₆ D = 4

= 5(1) + 2(3) – 6(4)

= 5 + 6 – 24

= 11 – 24

= –13

Therefore,

Log₆ (A⁵C² / D⁶) = –13

7 0
3 years ago
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