To effectively determine the correct answer, it would be helpful to write this into an algebraic expression. We let x as the number. We do as follows:
<span>Four times the square of a certain number increased by 6 times the number equals 108.
4x^2 + 6x = 108
The numbers can be either of the following since the equation generated was a quadratic equation which has two roots.
x = 4.5
x = -6 </span>
The irrational numbers are √10,√27,√99.
Answer:
Step-by-step explanation:
A) 5x - 7 = 5x becomes -7 = 0 if 5x is subtracted from both sides. This result is never true, so NO SOLUTION
B)3x−9=3(x−3) Performing the indicated multiplication, we get
3x - 9 = 3x - 9. This is always true, so there are INFINITELY MANY SOLUTIONS
C)2x−6=−2(x−3) Performing the indicated multiplication, we get
2x - 6 = -2x + 6. Adding 2x - 6 to both sides results in
4x - 12 = 0, or 4x = 12. Thus, the solution is x = 3. ONE SOLUTION
D)2x+6−5x=−3(x This equation is incomplete
Answer:
Answer ::+-6
Step-by-step explanation:
x:3=12:x
or, x/3 = 12/x
Doing cross multiplication,
x^2=36
Putting sqare root on both sides,
x= sqrt. 36
x= +- 6
Therefore x=+-6.
y = 4x - 3 would be it !!!!
