Ask question

Ask question

All categories

3 years ago

10

A random sample of n measurements is drawn from a binomial population with probability of success . Complete parts a through d b

elow. a. Give the mean and standard deviation of the sampling distribution of the sample proportion, . The mean of the sampling distribution of is nothing. The standard deviation of the sampling distribution of is nothing.

1 answer:

Dima020 [189]3 years ago

4 0

Complete question :

A random sample of n = 83 measurements is drawn from a binomial population with probability of success 0.4 . Complete parts a through d below. a. Give the mean and standard deviation of the sampling distribution of the sample proportion, . The mean of the sampling distribution of is nothing. The standard deviation of the sampling distribution of is nothing.

Answer:

Mean = 33.2000

Standard deviation = 4.4632

Step-by-step explanation:

Given that :

Sample size (n) = 83

Probability of success (p) = 0.4

q = p' = (1 - p) = 1 - 0.4 = 0.6

The mean of the sampling distribution :

Sample size * probability of success

n * p = 83 * 0.4 = 33.2000

The standard deviation of the sampling distribution :

σ=√(sample size * probability of success * (1 - p))

σ = √n * p * (1 - p)

σ = √(83 * 0.4 * 0.6)

σ = √19.92

σ = 4.46318

σ = 4.4632

You might be interested in

There is a rectangle with a length of 12.5x +5 and a width of 5 . What is the area of the triangle

krek1111 [17]

The answer would be 65

4 0

3 years ago

There are 16 boys and 19 girls in a class. The teacher calls the

san4es73 [151]

Answer:

1/12/2121 precent

Step-by-step explanation:

6 0

3 years ago

Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and

Brums [2.3K]

Answer:

$t=\frac{51.6-48}{\frac{1.1}{\sqrt{10}}}=10.349$

$p_v =P(t_9>10.349)=1.34x10^{-6}$

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the the actual mean is significantly higher than 48 MPa at 5% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X=51.6$ represent the sample mean

$s=1.1$ represent the standard deviation for the sample

$n=10$ sample size

$\mu_o =48$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the mean score is higher than 48, the system of hypothesis would be:

Null hypothesis: $\mu \geq 48$

Alternative hypothesis: $\mu > 48$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{51.6-48}{\frac{1.1}{\sqrt{10}}}=10.349$

Calculate the P-value

First we find the degrees of freedom:

$df=n-1=10-1=9$

Since is a one-side upper test the p value would be:

$p_v =P(t_9>10.349)=1.34x10^{-6}$

Conclusion

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the the actual mean is significantly higher than 48 MPa at 5% of significance.

5 0

3 years ago

HELP ASAP PLSSSSSSSSSS

inysia [295]

Answer:

Neighborhood Q appears to have a bigger family size

Step-by-step explanation:

Mean = the sum of all data values divided by the total number of data values

Number of families in Neighborhood Q = 9

Mean family size of Neighborhood Q:

= (2 + 5 + 4 + 3 + 2 + 5 + 3 + 6 + 5) ÷ 9

= 35 ÷ 9

= 3.888888...

Number of families in Neighborhood S = 9

Mean family size of Neighborhood S:

= (2 + 3 + 2 + 3 + 7 + 2 + 3 + 3 + 2) ÷ 9

= 27 ÷ 9

= 3

The mean family size of Neighborhood Q is 3.88.. and the mean family size of Neighborhood S is 3. Therefore, Neighborhood Q appears to have a bigger family size as it's average family size is bigger than that of Neighborhood S.

6 0

2 years ago

A frightened child is restrained by her mother as the child slides down a frictionless playground slide. If the force on the chi

MissTica

Answer:

Step-by-step explanation:

Given

Restrained Force $F=116 N$

Increase in Kinetic Energy $\Delta K.E.=30 J$

Distance moved d=1.9 m

Work done by all the forces is equal to change in Kinetic Energy of Object i.e. by gravity force, Normal force and Applied Force

$\Delta K.E.=W_g+W_f+W_N$

$30=W_g-F\cdot d$

$30=W_g-116\cdot 1.9$

$W_g=250.4 J$

(b)In absence of applied force thus

work done by gravity will be equal to change in kinetic Energy

change in Kinetic Energy $=210 J$

6 0

4 years ago