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kati45 [8]
3 years ago
8

A saleslady is paid a commission of 3% on goods worth over 100,000 and a salary 11,000 .If she had a20% salary increase and tota

l earnings of 22,200. Calculate the total amount received from sales
Mathematics
1 answer:
castortr0y [4]3 years ago
7 0

Answer:

I am not sure on the answer but i think its $9,000

Step-by-step explanation:

11,000x0.20=2,200

2,200+11,000=13,200

22,200-13,200=9,000

which would mean she got $9,000 from commissions.

if you did 100,000x0.03=3,000

9,000/3,000= 3

so she would have had 3 commissions worth over 100,000

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Somebody, please answer this!
Tresset [83]

Answer:

6:1:2.

Step-by-step explanation:

If Ben's score is  x  then Abel's is 6x and Cal's is 6/3 = 2x.

Then Abel's to Ben's to Cal's

= 6x : x : 2x

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3 years ago
The set for a school play needs a replica of a historic building painted on a backdrop that is 20 feet long and 16 feet high. Th
expeople1 [14]

Answer:

Stage crewmember's calculation is incorrect

Correct = 1/16x 1/16y

Step-by-step explanation:

Given that:

Dimension of backdrop : 20 feets long ; 16 feets high

Actual dimension of building : 320 feets long ; 256 feets high

The correct scale factor can be obtained thus :

Ratio of backdrop dimension to the actual dimension of building

Length : 20 / 320 = 1 /16

Height : 16 / 256 = 1/16

Hence, stage crewmember's calculation of (1/20x ; 1/20y) is incorrect.

5 0
3 years ago
A bank manager has developed a new system to reduce the time customers spend waiting for teller service during peak hours. The m
solong [7]

Answer:

Both the approach gave the same conclusion:

There is enough evidence to support the claim that the mean waiting time is shorter than six minutes

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 6 minutes

Sample mean, \bar{x} = 5.46 minutes

Sample size, n = 100

Alpha, α = 0.05

Sample standard deviation, s = 2.475 minutes

First, we design the null and the alternate hypothesis

H_{0}: \mu = 6\text{ minutes}\\H_A: \mu < 6\text{ minutes}

We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{5.36 - 6}{\frac{2.475}{\sqrt{100}} } = -2.5858

a) Use the critical value approach

Now, t_{critical} \text{ at 0.05 level of significance, 99 degree of freedom } = -1.6603Since, the calculated test statistic is less than the critical value of t, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Conclusion:

Thus, there is enough evidence to support the claim that new system reduces the time customers spend waiting for teller service during peak hours from the current 9 to 10 minutes to less than 6 minutes.

b) Use the p-value approach

The p-value can be calculated as:

P-value = 0.0055

Since the p-value is less than the significance level, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Conclusion:

Thus, there is enough evidence to support the claim that new system reduces the time customers spend waiting for teller service during peak hours from the current 9 to 10 minutes to less than 6 minutes.

5 0
4 years ago
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