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Ivanshal [37]
2 years ago
14

A town has two high schools. All of the 11th grade girls from both schools will combine to form a district debate team. Only 20

Mathematics
1 answer:
MariettaO [177]2 years ago
5 0

Answer:

<h2>60</h2>

Step-by-step explanation:

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Students make 93.5 ounces of liquid soap for a craft fair. They put the soap in ​5.5-ounce bottles and sell each bottle for ​$4.
s2008m [1.1K]

Answer:

$76.5

Step-by-step explanation:

93.5÷5.5=17

17×4.50=76.5

Therefore the answer is 76.5.

8 0
3 years ago
For what value of x is the rational expression below equal to zero?<br> 2-X<br> 2 + x
s344n2d4d5 [400]

Answer:

2

Step-by-step explanation:

If you divide 0 by any number you will get 0

If you will substitute x for 2 you will have:

2-2/2+2=0/4=0

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3 years ago
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20% of US High School teens vape. A local High School has implemented campaigns to reduce vaping among students and believes tha
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Answer:

10.93% probability of observing 51 or fewer vapers in a random sample of 300

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 300, p = 0.2

So

\mu = E(X) = np = 300*0.2 = 60

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.2*0.8} = 6.9282

What is the approximate probability of observing 51 or fewer vapers in a random sample of 300?

Using continuity corrections, this is P(X \leq 51 + 0.5) = P(X \leq 51.5), which is the pvalue of Z when X = 51.5 So

Z = \frac{X - \mu}{\sigma}

Z = \frac{51.5 - 60}{6.9282}

Z = -1.23

Z = -1.23 has a pvalue of 0.1093.

10.93% probability of observing 51 or fewer vapers in a random sample of 300

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3 years ago
La razon de 3 librasa $ 6.00​
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I would love to help you so much but I don't understand

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