Answer:
What's the question?
Step-by-step explanation:
Your struggling with
The intercepts of the third degree polynomial corresponds to the zeros of the equation
y = d*(x-a)*(x-b)(x-c)
Where a, b and c are the roots of the polynomial and d an adjustment coefficient.
y = d*(x+2)*(x)*(x-3)
Lets assume d = 1, and we get
y = (x+2)*(x)*(x-3) = x^3 - x^2 - 6x
We graph the equation in the attached file.
Answer:
x=-3
Step-by-step explanation:
If x=-3, then
x³+x²-2x+12=-27+9+6+12=-27+27=0
If this is true, then x+3 is a factor. So:
x³+x²-2x+12/x+3=x²-2x+4
So the factors of x³+x²-2x+12 are:
(x+3)(x²-2x+4)
((x²-2x+4) has no real roots)........
You got the answer already probably