Complete question :
Write a system of equations, with one equation describing the cost to bowl at Bowl-o-Rama and the other describing the cost to bowl at Bowling Pinz. For each equation, let x represent the number of games played and let y represent the total cost.
Bowl-O-Rama rents shoes for $2 and each game cost $2.50
Bowling Pinz rents shoes for $4 and each game cost $2
Answer:
Bowl-O-Rama:
y = $2 + $2.50x
Bowling pinz:
y = $4 + $2x
Step-by-step explanation:
The total cost is the sum of shoe rental plus the product of the unit game rate and the number of games played.
Total cost, y
x = number of games played
Bowl-O-Rama:
y = Shoe rent + (unit rate per game * number of games)
y = $2 + ($2.50 * x)
y = $2 + $2.50x
Bowling Pinz :
y = Shoe rent + (unit rate per game * number of games)
y = $4 + ($2 * x)
y = $4 + $2x
Answer: 47 students
Step-by-step explanation:
430 students went on a trip with the majority of them going on buses.
7 students however, had to use cars.
The number of students who used buses are:
= 430 - 7
= 423 students
The number of students in each bus is:
= No. of students taking buses / no. of buses
= 423 / 9 buses
= 47 students
Applying the formula for the area of a sector and length of an arc, the value of k is calculated as: 27.
<h3>What is the Area of a Sector?</h3>
Area of a sector of a circle = ∅/360 × πr²
<h3>What is the Length of an Arc?</h3>
Length of arc = ∅/360 × 2πr
Given the following:
- Radius (r) = 9 cm
- Length of arc = 6π cm
- Area of sector = kπ cm²
Find ∅ of the sector using the formula for length of acr:
∅/360 × 2πr = 6π
Plug in the value of r
∅/360 × 2π(9) = 6π
∅/360 × 18π = 6π
Divide both sides by 18π
∅/360 = 6π/18π
∅/360 = 1/3
Multiply both sides by 360
∅ = 1/3 × 360
∅ = 120°
Find the area of the sector:
Area = ∅/360 × πr² = 120/360 × π(9²)
Area = 1/3 × π81
Area = 27π
Therefore, the value of k is 27.
Learn more about area of sector on:
brainly.com/question/22972014
H(2)=5-F+g(2)=(f • h)(2)=f
-16, +2 are two nhmbers that multiply to -32 and add to -14
