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3 years ago

How do I find the answer to this? I’m struggling.

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

8 0

Ok. Add the hours worked that week. You get 41.75

He makes 11.50 for the first 40 hours so multiply those. You get $460.

There are 1.75 hours he gets overtime for. So multiply 1.75(11.50)(1.5). You’ll get $30.19. That’s his overtone pay so add it to the 460.

$490.19.

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Based on Pythagorean identities, which equation is true? A. Sin^2 theta -1= cos^2 theta B. Sec^2 theta-tan^2 theta= -1 C. -cos^2

Arturiano [62]

Answer:

Step-by-step explanation:

our basic Pythagorean identity is cos²(x) + sin²(x) = 1

we can derive the 2 other using the listed above.

1. (cos²(x) + sin²(x))/cos²(x) = 1/cos²(x)

1 + tan²(x) = sec²(x)

2.(cos²(x) + sin²(x))/sin²(x) = 1/sin²(x)

cot²(x) + 1 = csc²(x)

A. sin^2 theta -1= cos^2 theta

this is false

cos²(x) + sin²(x) = 1

isolating cos²(x)

cos²(x) = 1-sin²(x), not equal to sin²(x)-1

B. Sec^2 theta-tan^2 theta= -1

1 + tan²(x) = sec²(x)

sec²(x)-tan(x) = 1, not -1

false

C. -cos^2 theta-1= sin^2

cos²(x) + sin²(x) = 1

sin²(x) = 1-cos²(x), our 1 is positive not negative, so false

D. Cot^2 theta - csc^2 theta=-1

cot²(x) + 1 = csc²(x)

isolating 1

1 = csc²(x) - cot²(x)

multiplying both sides by -1

-1 = cot²(x) - csc²(x)

TRUE

3 0

3 years ago

Three consecutive integers can be represented by the variable n, n+1 and n+2. If the sum of three consecutive integers is 57, wh

pashok25 [27]

You have some unknown integer $n$ , and you know that adding this and the next two integers, $n+1$ and $n+2$ , gives a total of 57.

This means

$n+(n+1)+(n+2)=57$

The task is to find all three unknown integers. Notice that if you know the value of $n$ , then you pretty much know the value of the other three integers.

To find $n$ , solve the equation above:

$n+(n+1)+(n+2)=3n+3=57\implies 3n=54\implies n=\dfrac{54}3=18$

So if 18 is the first integer, then others must be 19 and 20.

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