Answer:
The correct options are 3, 4 and 5.
Step-by-step explanation:
It is given that an air balloon begins it's decent to the ground at 1000 ft above the ground and falls at a rate of 50 ft per minute.
It means the initial height of air balloon is 1000. So, the y-intercept is (0,1000).
The ball falls at a rate of 50 ft per minute. So, the rate of change is
The height of balloon is defined as
![[\because y=mx+b]](https://tex.z-dn.net/?f=%5B%5Cbecause%20y%3Dmx%2Bb%5D)
Where, x is time in minutes.
The balloon will reach the ground when h(x)=0
Therefore the options 3, 4 and 5 are correct.
Electrons do not have FEET
Answer:
Account A: Decreasing at 8 % per year
Account B: Decreasing at 10.00 % per year
Account B shows the greater percentage change
Step-by-step explanation:
Part A: Percent change from exponential formula
f(x) = 9628(0.92)ˣ
The general formula for an exponential function is
y = ab^x, where
b = the base of the exponential function.
if b < 1, we have an exponential decay function.
ƒ(x) decreases as x increases.
Account A is decreasing each year.
We can rewrite the formula for an exponential decay function as:
y = a(1 – b)ˣ, where
1 – b = the decay factor
b = the percent change in decimal form
If we compare the two formulas, we find
0.92 = 1 - b
b = 1 - 0.92 = 0.08 = 8 %
The account is decreasing at an annual rate of 8 %.The account is decreasing at an annual rate of 10.00 %.
Account B recorded a greater percentage change in the amount of money over the previous year.
The distance between the horizontal legs be the distance between the 'x' values '-5' and '2'. 2+5=7 (It is +5 because the distance between -5 and 0 is 5*)
The distance between the horizontals is 7
Same with the vertical points, as the distance is 2. (1+1=2)
Considering that the pythagorean theorem is the a^2+b^2=c^2, and 'a' and 'b' are the sides, then you plug in '7' and '2', making the equation 7^2+2^2=c^2
49+4=c^2
53=c^2
c=sqrt(53)
Hope this helps.
Answer:
QR / SQ = SQ / TQ
Step-by-step explanation:
∠QST = 90 - ∠Q
∠R = 90 - ∠Q
∠QST = ∠R
ΔQST ~ ΔQRS
SQ / TQ = QR / SQ
