Question

A company plans to enclose three parallel rectangular areas for sorting returned goods. The three areas are within one large rectangular area and yd of fencing is available. What is the largest total area that can be​ enclosed

Answer 1

Answer:

A lot of information is missing, so I looked for similar questions:

• 1,064 yd of fencing is available

since 1,064 is the perimeter and we have a rectangle, we can write the perimeter equation as: 2L + 2W = 1,064

area = L · W

2W = 1,064 - 2L

W = 532 - L

now we replace in the area equation:

area = (532 - L) · L = -W² + 532W (quadratic equation format)

the value of L as our X coordinate:

L = 532 / 2 = 266

W = 532 - 266 = 266

area = -(266)² + (532 x 266) = -70,756 + 141,512 = 70,756 sq yards

or

area = 266 · 266 = 70,756 sq yards

When you have a rectangle, the largest possible area is a square, where both sides have the same length.