Y-axis, because what i’ve been taught with coordinates, is you crawl before you walk which means is first it’s x-axis then y-axis. so (0,4) would be on the y-axis. :)
![\bf \stackrel{\textit{volume of a cylinder}}{V=\pi r^2 h}~\hspace{7em}\stackrel{\textit{volume of a cone}}{V=\cfrac{\pi r^2 h}{3}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{volume of a cylinder}}{V=24\pi }~\hspace{7em}\stackrel{\textit{volume of a cone}}{V=\cfrac{24\pi }{3}}\implies V=8\pi](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bvolume%20of%20a%20cylinder%7D%7D%7BV%3D%5Cpi%20r%5E2%20h%7D~%5Chspace%7B7em%7D%5Cstackrel%7B%5Ctextit%7Bvolume%20of%20a%20cone%7D%7D%7BV%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bvolume%20of%20a%20cylinder%7D%7D%7BV%3D24%5Cpi%20%7D~%5Chspace%7B7em%7D%5Cstackrel%7B%5Ctextit%7Bvolume%20of%20a%20cone%7D%7D%7BV%3D%5Ccfrac%7B24%5Cpi%20%7D%7B3%7D%7D%5Cimplies%20V%3D8%5Cpi)
notice the volumes, the cone's volume is really one-third that of the cylinder, assuming "h"eight and "r"adius is the same on both.
The answer is C.
3 (20-14)=44
(distribute the 3, then subtract)
Given that:
Perimeter=194 cm
Width=w
Length, L= 4w-3
Formula for perimeter of rectangle:
P=2(L+W)
Put values
194=2(4w-3+w)
194=2(5w-3)
Divide both sides by 2.
97=5w-3
Add 3 to both sides
100=5w
w=20
So length= 4 (20) -3 = 80-3 =77 cm
and width= 20 cm
Answer: Length=77 cm and width=20 cm
Answer:
Step-by-step explanation:
The number of ways that you can draw 2 balls without restriction is 10 * 10 = 100
Two balls will give you 2 or less (meaning 1) or 2*2 = 4
Four ways are possible
2 and 2
2 and 1
1 and 2
1 and 1
4/100 = 1/25 is the probability of making this happen.
