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2 years ago

I dont understand how to solve the equation?

Mathematics

2 answers:

kramer2 years ago

7 0

3/8 is the answer to you’re problem

Sati [7]2 years ago

3 0

It is 3:8 or 3/8. All of the scales simplify to 3/8.

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Ann's rent increased from $1,200 to $1,350 <br> By what percent did her rent increase

Ierofanga [76]

Answer:

1% of 1200 is 12, so to find this we multiply 12 until we get 150

150/12 = 12.5

12.5%

5 0

3 years ago

Can anyone help me <br>2n +5=7

zavuch27 [327]

Answer:N=1

Step-by-step explanation: when trying to figure out the value to solve for “N” you begin with taking out any number next to variable . For this case you subtract 5 from the product (7) n should get 2n=2 and the value for N is 1

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3 years ago

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The area of the rectangle shown below is 6x2+11x-7 square units. the length is 2x-1 what is the width

Hitman42 [59]

Answer:

Width is 3x+7 units

Step-by-step explanation:

In the attached file

5 0

3 years ago

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URGENT HELP YALL WITH THIS. I WILL MARK YOU BRAINLIEST

Reptile [31]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

$(9x + 17) +2 \times ( 5x + 15 ) + (6x - 12) = 360 \\$

$9x + 17 + 10x + 30 + 6x - 12 = 360 \\$

$9x + 10x + 6x + 17 + 30 - 12 = 360 \\$

Collect like terms

$25x + 35 = 360$

Subtract sides 35

$25x + 35 - 35 = 360 - 35$

$25x = 325$

Divide sides by 25

$\frac{25x}{25} = \frac{325}{25} \\$

$x = 13$

Thus ;

$RQ \: \: arc =2 \times (5x + 15)$

$RQ \: \: arc = 10x + 30$

$RQ \: \: arc = 10(13) + 30$

$RQ \: \: arc = 130 + 30$

$RQ \: \: arc = 160°$

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7 0

3 years ago

The volume of two spheres are 327\pi in^{3} and 8829\pi in^{3}

Crazy boy [7]

A dimension of a sphere is its radius, so it correlates with its volume, thus

$\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array}\\\\
-----------------------------$

$\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\
%The volume of two spheres are 327\pi in^{3} and 8829\pi in^{3}
\cfrac{small}{large}\qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\implies \cfrac{s}{s}=\cfrac{\sqrt[3]{327}}{\sqrt[3]{8829}}\qquad 
\begin{cases}
8829=3\cdot 3\cdot 3\cdot 327\\
\qquad 3^3\cdot 327
\end{cases}$

$\bf \cfrac{s}{s}=\cfrac{\sqrt[3]{327}}{\sqrt[3]{3^3\cdot 327}}\implies \cfrac{s}{s}=\cfrac{\underline{\sqrt[3]{327}}}{3\underline{\sqrt[3]{327}}}\implies \cfrac{s}{s}=\cfrac{1}{3}$

6 0

3 years ago