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trapecia [35]
3 years ago
9

What are 2 ratios equivalent to 3:12

Mathematics
1 answer:
Kruka [31]3 years ago
3 0

Answer:

6/24

Step-by-step explanation:

Well, this ratio would be written as 6/24. Using your knowledge of equivalent fractions, you can see that 3/12 = 6/24 (multiply the numerator and denominator of 3/12 by 2 and you get 6/24.

Hope this helps you.

Mark as Brainliest Please.!!!

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The enrollment in college A may be modeled by y = 0.025x + 1.45, and the enrollment in college B may be modeled by y = 0.037x +
Brrunno [24]

The first one would be it.


7 0
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Una sustancia se encuentra en 15°c pero a partir de comienzo de un experimento su temperatura disminuye de manera uniforme a raz
bija089 [108]

Answer:

1= -15 °C

2= 7 minutos y medio

Step-by-step explanation:

1= colo la temperatura va bajando 2 grados cada minuto lo único que hay que hacer es restarle 30 °C a 15 y nos da -15 ° C

2= Solo divides 15 entre 2 y ya.

6 0
3 years ago
a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-
Tresset [83]

Answer:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

M = \frac{1}{2}(Lower + Upper)

Where

Lower \to Lower class interval

Upper \to Upper class interval

So, we have:

Class 63-65:

M = \frac{1}{2}(63 + 65) = 64

Class 66 - 68:

M = \frac{1}{2}(66 + 68) = 67

When the computation is completed, the frequency distribution will be:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

\bar x = 70.2903

\sigma = 3.5795

<em>See attachment for result of 1-VarStats</em>

8 0
3 years ago
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Factor 4a2 - 25.<br><br> A. (2a + 5)(2a + 5)<br> B. (2a - 5)(2a - 5)<br> C. (2a - 5)(2a + 5)
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This is the diference of 2 perfect squares. 4 is a perfect square, x^2 is a perfect square, and 25 is a perfect square. The pattern for this is (ax + b)(ax - b). Our a is 2 since 2*2 = 4, and our b is 5 since 5*5 = 25. So your factors are (2a+5)(2a-5), choice C.

3 0
3 years ago
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