What is 5(2x - 7) = step by step equation need please and thank you

Mathematics

1 answer:

stepladder [879]3 years ago

3 0

5(2x-7)
= (5)(2x+-7)
= (5)(2x)+(5)(-7)
= 10x - 35

You might be interested in

a basketball coach keeps track of the points scored per game for all her players.she gives a trophy to the player with the highe

podryga [215]

The answer would be C. When you calculate the mean, it includes every number for a certain period of time into things and averages it out. The median does not average out all the numbers.

4 0

3 years ago

Read 2 more answers

How many significant digits are in this number? 4,000,000?

erma4kov [3.2K]

Just one which is the 4 but you have to put the zeros in because if you won 4,103,002 on the lottery you would say oh i won 4 million you wouldn’t say i won 4

5 0

3 years ago

NEED HELP ASAP i don’t know the answer

Effectus [21]

It’s A, pls mark brainliest

4 0

3 years ago

Help please I need it know

elena-14-01-66 [18.8K]

On 15 angle 1 and 2 would be 150 degrees i think, i could be wrong.
On 16 angle 1 would be 140 degrees and angle 2 would be 40 degrees. hope this helps

8 0

3 years ago

If $8700 is invested at 3% annual simple interest, how much should be invested at 6% annual simple interest so that the total ye

True [87]

First off, see how much 8700 as principal, yields at 3% APR
that is $\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$8700\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &1
\end{cases}$

it will yield some amount

subtract that amount from 393
the difference is how much the yield will be on the 6% investment
so

$\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\quad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$8700\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &1
\end{cases}
\\\\\\
\implies \boxed{?}\\\\
-----------------------------\\\\
\textit{how much to invest at 6\%?}
\\\\\\
$

$\bf \qquad \textit{Simple Interest Earned}\\\\
(393-\boxed{?}) = Prt\quad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
t=years\to &1
\end{cases}
\\\\\\
\textit{solve for "P", to see how much should the Principal be}\\\\
\textit{keep in mind that }P+\boxed{?}=393\leftarrow \textit{both yields added}$

6 0

3 years ago