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Ede4ka [16]
3 years ago
9

Add polynomials: (3-4x + 8x^2) + (-6 + 2x - 5x^2)

Mathematics
1 answer:
seropon [69]3 years ago
4 0

Answer:

3x^2-2x-3

Step-by-step explanation:


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PLEASE HELP! ASAP! WILL MARK BRAINLIEST IF CORRECT!!!!!
Volgvan

Answer:

D.............................................

Step-by-step explanation:

im sorry if im wrong

6 0
2 years ago
The area of a right triangle with one leg measuring 5ft and hypotenuse measuring 13ft is
nexus9112 [7]
Calculating the other leg:
other leg^2 = 13^2 - 5^2
other leg^2 = 169 -25
other leg^2 = 144
other leg = 12

Area = .5 * 12 *5
Area = 30 sq feet
answer is A


6 0
3 years ago
Find the volume of the shaded figure by subtracting the smaller volume from the larger
alekssr [168]

Answer:

a. 9a^3 - 9ab^2

b. 9a(a^2 - b^2)

Step-by-step explanation:

a.

Volume = l*w*h

Volume_{smaller} = l*w*h

Where, l = 9a, w = b, h = b

Volume_{smaller} = 9a*b*b = 9ab^2

Volume_{larger} = l*w*h

Where, l = 9a, w = a, h = a

Volume_{smaller} = 9a*a*a = 9a^3

Volume of the shaded figure = 9a^3 - 9ab^2

b. 9a^3 - 9ab^2 expressed in factored form:

Look for the term that is common to 9a³ and 9ab², then take outside the parenthesis.

9a^3 - 9ab^2 = 9a(a^2 - b^2)

6 0
3 years ago
Suppose a normal distribution has a mean of 48 and a standard deviation of 2. What is the probability that a data value is betwe
stepan [7]

Answer:

Choice D.  15.2%

Step-by-step explanation:

We have a normal...

mean u = 48

standard deviation s = 2

We want P(43 < X < 46)

We standardize.

Consider  P(43 < X)  = P( (43 - 48)/2 < Z) = P(-2.5 < Z)

P( X < 46) = P( Z < (46 - 48)/2 ) = P(Z < -1)

We want  P( -2.5 < Z < -1)

Look at Z-scores.

P( Z < -2.5)  = 0.0062

P(Z  < -1) = 0.1587

so  P(-2.5 < Z < -1) =  P(Z < -1) - P(Z < -2.5) = 0.1587 - 0.0062 = 0.1525 = 15.2%

about

3 0
3 years ago
A rectangular public park has an area of 3,600 square feet. It is surrounded on three sides by a chain link fence. If the entire
Dafna11 [192]

Answer:

If length of the field is 30 ft, then width is 120 ft.

If the  length of the field is 60 ft, then width is 60 ft.

Step-by-step explanation:

Let us assume the length of the rectangular park = L ft

Let us assume the breadth of the rectangular park = B  ft

Now, AREA of the given park =  L x B

⇒ L x B  = 3,600 sq ft   ... (1)

Also, the perimeter of three sides  = 180 ft

⇒ 2 L +  B  = 180  ..... (2)

Now, from (1) and (2), we get:

L x B  = 3,600

2 L +  B  = 180   ⇒ B  = 180 - 2 L

Substitute this in(1) , we get:

L x B  = 3,600   ⇒ L x (180 - 2 L)  = 3600

\implies  180 L - 2L^2 = 3600\\\implies L^2 -90L + 1800 = 0\\\implies (L-30)(L-60)= 0

⇒ L = 30 or L  = 60

So, if L  = 30  ft , then B = 180 - 2L  =  180 - 60 = 120 ft

So, if L  = 60  ft , then B = 180 - 2L  =  180 - 120 = 60 ft

So, if length of the field is 30 ft, then width is 120 ft.

And if the  length of the field is 60 ft, then width is 60 ft.

4 0
3 years ago
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