All categories

3 years ago

I need help please !!

Mathematics

1 answer:

kondor19780726 [428]3 years ago

8 0

It’s honestly really confusing I would skip it cuz imma sophomore and ion know

You might be interested in

In the given right triangle, find the length of the hypotenuse, AB, if BC = 6 and AC = 5.

wolverine [178]

*Use the Pythagorean Theorem

a^2 + b^2 = c^2

6^2 + 5^2 - c^2
36 + 25 = c^2
61 = c^2 *Square root 61

c^2 (c squared) = about 7.8

6 0

3 years ago

Lisa knit 3/12 foot of a scarf on Saturday. She knit 8/12 foot of a scarf on Sunday.

Vesna [10]

Answer:

C - 5/12 of a foot

Step-by-step explanation:

Subtract the numerators from 8/12 - 3/12 - keeping the denominator

8 - 3 = 5

5/12

7 0

3 years ago

Find the midpoint between (-1, -1) and (-9,6).?

ryzh [129]

Answer:

(-5,-3.5) is the midpoint

Step-by-step explanation:

See photo for the step-by-step explanation

7 0

3 years ago

Read 2 more answers

A spherical balloon currently has a radius of 19cm. If the radius is still growing at a rate of 5cm or minute, at what rate is a

miv72 [106K]

Answer:

22670.8 cm³/min

Step-by-step explanation:

Given:

Radius of the balloon at a certain time (r) = 19 cm

Rate of growth of radius is, $\frac{dr}{dt}=5\ cm/min$

The rate at which the air is pumped in the balloon can be calculated by finding the rate of increase in the volume of the balloon.

So, first we find the volume of the sphere in terms of 'r'. As the balloon is spherical in shape, the volume of the balloon is equal to the volume of a sphere. Therefore,

Volume of balloon is given as:

$V=\frac{4}{3}\pi r^3$

Now, rate of increase of volume is obtained by differentiating both sides of the equation with respect to time 't'.

Differentiating both sides with respect to time 't', we get:

$\frac{dV}{dt}=\frac{d}{dt}(\frac{4}{3}\pi r^3)\\\\\frac{dV}{dt}=\frac{4\pi}{3}(3r^2)(\frac{dr}{dt})\\\\\frac{dV}{dt}=4\pi r^2(\frac{dr}{dt})$

Now, plug in 19 cm for 'r', 5 cm per minute for $\frac{dr}{dt}$ and solve for $\frac{dV}{dt}$ . This gives,

$\frac{dV}{dt}=4\pi (19 cm)^2(5\ cm/min)\\\\\frac{dV}{dt}=4\times 3.14\times 361\times 5\ cm^3/min\\\\\frac{dV}{dt}=22670.8\ cm^3/min$

Therefore, the rate at which the air is being pumped into the balloon is 22670.8 cm³/min.

4 0

4 years ago

3x +4= 9x + 3 I need help PLEASEEE

mario62 [17]

Add 3x and 9x together and then your equation should look like this, 12x + 7

7 0

3 years ago

Read 2 more answers