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qaws [65]
4 years ago
11

Find the point of a line segment with endpoints (4,-4) and (-10,6)

Mathematics
1 answer:
geniusboy [140]4 years ago
6 0
Is there a grid or something? You'll need that to solve this problem.
Find the 4 on the x axis and the -4 on the y axis. The point where the two lines meet is the first endpoint. Find the -10 on the x axis and the 6 on the y axis. The point where the two lines meet is the second endpoint.
Hope this helped :)
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Tomas needs exactly 666 potatoes to make 121212 potato pancakes.
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3 years ago
One focus of a hyperbola is located at (−6, 2). One vertex of the hyperbola is located at (−4, 2). The center is (−1, 2).
Valentin [98]

Answer:

(x+1)^2/9 - (y-2)^2/16 = 1

Step-by-step explanation:

As the center and the vertex of the hyperbola forms a horizontal segment (they have the same y value), we can use the hyperbola equation with horizontal axis:

(x-h)^2/a^2 - (y-k)^2/b^2 = 1

For this equation, the center of the hyperbola is (h,k), the vertix is (h±a, k) and the focus is (h±c, k), where c^2 = a^2 + b^2

So if the center is (-1,2), we have h = -1 and k = 2

If the vertex is (-4,2), we have that h-a = -4, so a = 3

If the focus is (-6,2), we have that h-c = -6, so c = 5

Now, finding b, we have:

5^2 = 3^2 + b^2

b = 4

So our equation is:

(x+1)^2/9 - (y-2)^2/16 = 1

8 0
4 years ago
Read 2 more answers
5n+35=75 what is the answer
Sergio [31]

Answer:

n=8

Step-by-step explanation:

5(8)=40

40 +35=75

glad to help:)

3 0
3 years ago
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What is 8/10 if 24 students
MariettaO [177]

Answer:

About 19 students

Step-by-step explanation:

8/10 = 0.80

.80 x 24 ≈ 19.2

Round to 19

3 0
3 years ago
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Algebra 2 <br> 50 POINTS <br> HELP
xenn [34]

Answer:

{-3, 2}U{2, 5}

Step-by-step explanation:

For an equation to be negative, it would need to be in a negative range (below the x-axis or the coordinates are negative y-values). Therefore, we can examine this question and see that the graph is negative when the function crosses the x-axis at -3 and it remains negative until you reach 2 on the x-axis.

Therefore, the first set of negative values is (-3, 2).

Secondly, applying the same logic as before, the function decreases at 2 and then touches the x-axis again at 5. Therefore, the second negative value would be (2, 5).

The negative values are {-3, 2}U{2, 5}.

6 0
4 years ago
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