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vovangra [49]
3 years ago
7

What is another way to describe the following expression? 5−(x+y)tothepowerof3

Mathematics
1 answer:
love history [14]3 years ago
4 0
Another way to answer this question would be(X+y)^3-5
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Help me solve please
Alex Ar [27]

Answer:

Step-by-step explanation:

The addition of angles ABD and DBC make up the larger angle ABC. We know that angle ABD = 65 and DBC = 60, therefore

angle ABC = 65 + 60 and

angle ABC = 125 degrees

5 0
3 years ago
Find the difference of the two polynomials : (2t^3 + 3t -4)-(4t^2 - 6t)
Natalija [7]
Distribute the - which changes the signs in the second parenthesis.
2t^3 + 3t - 4 - 4t^2 + 6t
Combine like terms, must have same exponent. Write in order of degree.
2t^3 - 4t^2 + 9t - 4
3 0
3 years ago
Cheryl and Marcus are going to make 2 batches of muffins. the smaller batch is 2/3 the size of the larger batch. the recipe for
MrMuchimi
The smaller batch is 2/3 of the large batch so anser is2/5

4 0
3 years ago
Read 2 more answers
3[ (5)/(-9) (6)/(-2)]-2[(0)/(-2)(2)/(-4)]
Anika [276]
5 is the correct answer I believe
7 0
2 years ago
Read 2 more answers
Can someone help me?
mestny [16]

Answer:

Step-by-step explanation:

To do this, we must use the unit circle. At the angle \frac{\pi }{6} the coordinate pair is (\frac{\sqrt{3} }{2}, \frac{1}{2}) and the hypotenuse is 1

Now that we know these we can start using the trig functions

sin = y

cos = x

tan = \frac{y}{x}

And the other functions would be the reciprocal of these

csc = \frac{1}{y}

sec = \frac{1}{x}

cot = \frac{x}{y}

This would mean that

sinx = \frac{1}{2}

cosx =\frac{\sqrt{3} }{2}

tanx =\frac{1}{\sqrt{3} } or \frac{\sqrt{3} }{3} if you're supposed to rationalize your denominators

cscx = 2

secx = \frac{2}{\sqrt{3} } or \frac{2\sqrt{3} }{3}

cot = \sqrt{3}

6 0
2 years ago
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