Gloria uses 2/5 hours of butter to make eats 1/3 of a pound of jelly. how much jelly can she make with 1 ounce of butter

goblinko [34]

The answer to this math problem is the multiple is 1 5 13

7 0

3 years ago

How is the process of finding the surface area of a rectangular prism the same as finding the surface area of a triangular prism

harina [27]

Answer:

see the explanation

Step-by-step explanation:

we know that

The surface area of a prism is given by the formula

$SA=2B+PH$

where

B is the area of the base

P is the perimeter of the base

H is the height of the prism

For both prism the formula is the same

How is it different?

Rectangular prism

The area of the base is given by the formula

$A=LW$ -----> is the area of rectangle

where

L is the length and W is the width of rectangle

The perimeter of the base is given by

$P=2(L+W)$ ---> is the perimeter of rectangle

The height H is the same in both cases

Triangular prism

The area of the base is given by the formula

$A=\frac{1}{2} (b)(h)$ -----> is the area of the triangular base

where

b is the base of triangle and h is the height of triangle

The perimeter of the base is given by

$P=(a+b+c)$ ---> is the perimeter of triangle

where

a, b and c are the length sides of triangle

The height H is the same in both cases

3 0

3 years ago

Read 2 more answers

Need to know please help me !!!

LenKa [72]

Answer:

9.5 feet/ 1 second is your unit rate

Step-by-step explanation:

In order to make a unit rate you have to make the denominator 1 so it can be a whole number which means you divide by the denominator on both sides both numerator and denominator.

3 0

3 years ago

please factor completely !Thank yoy

Vilka [71]

You can download the app photo math and that will help you

8 0

3 years ago

Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x.

Leni [432]

Answer:

a)

$g(2.9) \approx -6.6$

$g(3.1) \approx -3.4$

b)

The values are too small since $g''$ is positive for both values of $x$ in. I'm speaking of the $x$ values, 2.9 and 3.1.

Step-by-step explanation:

a)

The point-slope of a line is:

$y-y_1=m(x-x_1)$

where $m$ is the slope and $(x_1,y_1)$ is a point on that line.

We want to find the equation of the tangent line of the curve $g$ at the point $(3,-5)$ on $g$ .

So we know $(x_1,y_1)=(3,-5)$ .

To find $m$ , we must calculate the derivative of $g$ at $x=3$ :

$m=g'(3)=(3)^2+7=9+7=16$ .

So the equation of the tangent line to curve $g$ at $(3,-5)$ is:

$y-(-5)=16(x-3)$ .

I'm going to solve this for $y$ .

$y-(-5)=16(x-3)$

$y+5=16(x-3)$

Subtract 5 on both sides:

$y=16(x-3)-5$

What this means is for values $x$ near $x=3$ is that:

$g(x) \approx 16(x-3)-5$ .

Let's evaluate this approximation function for $g(2.9)$ .

$g(2.9) \approx 16(2.9-3)-5$

$g(2.9) \approx 16(-.1)-5$

$g(2.9) \approx -1.6-5$

$g(2.9) \approx -6.6$

Let's evaluate this approximation function for $g(3.1)$ .

$g(3.1) \approx 16(3.1-3)-5$

$g(3.1) \approx 16(.1)-5$

$g(3.1) \approx 1.6-5$

$g(3.1) \approx -3.4$

b) To determine if these are over approximations or under approximations I will require the second derivative.

If $g''$ is positive, then it leads to underestimation (since the curve is concave up at that number).

If $g''$ is negative, then it leads to overestimation (since the curve is concave down at that number).

$g'(x)=x^2+7$

$g''(x)=2x+0$

$g''(x)=2x$

$2x$ is positive for $x>0$ .

$2x$ is negative for $x$ .

That is, $g''(2.9)>0 \text{ and } g''(3.1)>0$ .

So $2x$ is positive for both values of $x$ which means that the values we found in part (a) are underestimations.

6 0

4 years ago