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saul85 [17]
3 years ago
15

1/2÷5= to a improper fraction

Mathematics
1 answer:
Leokris [45]3 years ago
5 0
1/10
hope this helps u out!
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(X^4-81)/x^3+3x^2+9x+27
Iteru [2.4K]

Answer:

x-3

Step-by-step explanation:

(x^2-9)(x^2-9)/x^2*(x+3)+9(x+3)

(x+3)*(x^2+9)/(x+3)*(x^2+9) cross multiply

(x^2+9)*(x+3)/(x^2+9) cross multiply

x+3 final anser

6 0
3 years ago
GEOMETRY HELP ASAP!!!!!!!!!!!!!!!!!!!
vovangra [49]
Area of equilateral triangle = a^2/4 * √3 so side of triangle = a

but if area of equilateral triangle =  area of square multiplied by √3 then area of square = a^2 / 4 so side of square = a/2

the ratio length of side triangle to length side of square = a: a/2 that means the side of triangle is doubled the side of square

answer
a) 2:1
6 0
3 years ago
If 843 units cost $16,421.40 to produce, how much does each unit cost to produce to the nearest cent?
Alex_Xolod [135]
<span>It costs 19.48, because $16,421.40 / 843 comes out to 19.479, and 19.479 rounds to 19.48. So the answer is B $19.48</span>
8 0
3 years ago
Ratio And Proportion
Allushta [10]

Answer:

11200 for 7 engines for a total of 80 hours

Step-by-step explanation:

You have 8 engines burning 12000 .for 10 hours.

Divide 10 hours into 12000=1200 PER hour.

1200 ÷8 engines = 140 per hour per engine.

140 × # of hours (12)=1680 for 12 hours per engine.

# of engines × 1680 for 12 hour/per engine

5×1680 = 8400 of fuel for 12 hours/5 engine

Then you have 2 that runs 10 hours

2 × 140 per hour per engine =280 × 10 =2800 for 2 engines for 10 hours

8400. + 2800= 11200 of fuel for 6 engines

4 0
3 years ago
Which ordered pair is the solution to the system of equations? {y=3x−102x+3y=3
uysha [10]
(3,-1) for sure i took the test 100% 
hope i helped out 
8 0
3 years ago
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