Given that the number of drivers who travel between a particular origin and destination during a designated time period has a Poisson distribution with parameter μ = 20 (suggested in the article "Dynamic Ride Sharing: Theory and Practice"†).

a) $P(X\leq 15) = 0.1565=0.157$

b) $P(X>26) =1-F(26)\\= 1-0.9221\\=0.0779=0.078$

c) $P(15\leq x\leq 26)\\=F(26)-F(14)\\=0.9221-0.1049\\=0.8172=0.817$

d) 2 std dev = 2(20) =40

Hence 2 std deviation means

20-40, 20+40

i.e. (0,60)

$P(0$

5 0

3 years ago

B= Round your answer to the nearest hundredth

vodomira [7]

Answer:

53.13 degrees

Step-by-step explanation:

3 0

2 years ago

Which of the following does an appropriately cautious reading of a receipt entail? I. Making sure that the items charged are the

Black_prince [1.1K]

An appropriate cautious reading of a receipt entail making sure that the

items charged are the same as the items received and checking to see if all

of the discounts were applied properly,

When an item is bought, a receipt is usually issued which confirms that

payment has been made for the goods or services. Receipt however should

be properly checked to detect any error in the course of the transaction.

Making sure that the items charged are the same as the items received and

checking to see if all of the discounts were applied properly should be done

to avoid shortages of the resources of the parties involved.

Read more on brainly.com/question/25539176

8 0

3 years ago