We have the following data:
Margin of Error = E = 2.7 % = 0.027
Sample size = n = 900
Proportion of adults in favor = p = 60% = 0.6
We need to find the confidence level. For this first we need to find the z value.
The margin of error for a population proportion is given as:

Using the values, we get:
As, seen from the z table, z=1.65 corresponds to the confidence level 90%. So, the answer to this question is option B
Answer:
6,12,18,24,30,36,42,48,54,69
C = 2 * 3.14 * 4 = 25.1 to nearest tenth ( 1 decimal place)