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ASHA 777 [7]
3 years ago
8

Find sin(β) in the triangle.

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
5 0

Answer:

4/5

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • A right angled triangle with sides as 3 , 4 and 5 cm .

We need to find the value of sin(β) in the given triangle . We know that the ratio of sine is ,

:\implies sin(β) = p/h

  • Where p is perpendicular and h is hypontenuse.

:\implies sin(β) = 4/5

<h3>Hence the required answer is 4/5.</h3>
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The answer is D) 72, 108

First you have to find out the measure of the two other angles in the triangle. Those two angles will be equivalent.

Because the sum of all three angles in a triangle is 180, you subtract 36 from it (180 - 36 = 144) then divide by 2 (144/2 = 72).

So, the two angles at the bottom of the triangle are each 72. Because those angles are supplementary to the angles at the top of the trapezoid, you subtract 72 from 180 (180 - 72 = 108).

108 + 108 = 216

The sum of all the angles in a trapezoid is 360, so subtract 216 from 360 (360 - 216 = 144) then divide by 2 (144/2 = 72)
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The line segments AA' and BB' are parallel and congruent

Step-by-step explanation:

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Correct on EDGE2021

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