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Sati [7]
2 years ago
10

What is the product (x-3)(2x^2-5x + 1)

Mathematics
1 answer:
Reika [66]2 years ago
4 0
F '(x<span>) = </span>2(3x2<span> + 5) + 6x(</span>2x<span> - </span>1<span>) ... + </span>3), s(x<span>) = </span>x<span> - 4. Use the </span>product<span> rule table. below to get: r'(</span>x) = 20x + 11. s'(x<span>) = </span>1<span> ... f'(</span>x) = (x<span> - 4</span>)(20x + 11) - (5x<span> - </span>2)(2x<span> + </span>3)/(x<span> - 4)</span>2<span>.</span>First, we will distribute 2x<span> to (</span>x<span> + 5), then we will distribute </span>3<span>. ... </span>5x<span>. That is,. multiplying binomials. 6x − </span>x<span>= </span>5x<span>. Example </span>2<span>. Multiply (3x − </span>1)(x<span> + </span>2). Answer. 3x2<span> + </span>5x<span> 


</span>
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Read 2 more answers
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
yan [13]

Answer:

1. ║u-z║= 5.66

2.║v-w║=6.0

3. ║w-u║=6.08

4.║v-u║=7.81

Step-by-step explanation:

The vectors are given as;

u = <-1, -3>, v = <5,-8>, w = <5, -2>, and z = <3, 1>.

To find the magnitude of the vectors;

1. ║u-z║

<-1 - 3> = <-4  and < -3 - 1> = <-4

║<-4,-4> ║= √{ -4²+-4²} = √32 = 5.66

2.║v-w║

   <5,-8> - <5,-2>

   <5-5> , <-8--2>

   <0,-6>

    ║<0,-6>║= √{0²+ -6²} = √36 = 6

3. ║w-u║

    <5,-2> - <-1,-3>

    <5--1> , <-2--3>

    <6,1>

    ║6,1║= √{6²+1²} = √36+1 = √37 = 6.08

4.║v-u║

   <5,-8> - <-1,-3>

    <5--1> , <-8--3>

    < 6 , -5 >

    ║6,-5║= √{6²+-5²} = √36+25 =√61 = 7.81

   

   

   

   

   

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